Give square triangle ABC with B = 60⁰ , A = 90⁰ and AB = 4cm

Calculator : AC and BC 

Give \(P=\dfrac{ax^{2\:}+bx+c}{a'x^2+b'x+c'}\)

Demonstrate if \(\dfrac{a}{a'}=\dfrac{b}{b'}=\dfrac{c}{c'}\) then P does not depend on x

Calculate expression value :

a) 4xy³ + \(\dfrac{1}{3}\)xy⁸ + \(\dfrac{2}{5}xy^3\)+ \(\left(-\dfrac{1}{3}\right)xy^8\) when x = \(\dfrac{2}{3}\) ; y = \(-\dfrac{1}{2}\)