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Run my EDM
21/03/2017 at 21:25
Answers
3
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How many positive numbers \(n\) satisfy that \(n^3-3n^2+2\) is a prime number?

  • ...
    Lê Anh Tú 25/03/2017 at 22:17

    Have: n3 - 3n2 + 2 = n3 - n2 - 2n2 + 2

    = n2(n - 1) - 2n2 + 2

    It is easy to see that n2(n - 1) is an even number because it contains n(n - 1) which is the product of two consecutive natural numbers, so n2(n - 1) - 2n2 + 2 is an even number

    But n3 - 3n2 + 2 = n2(n - 1) - 2n2 + 2 is a prime number so n3 - 3n2 + 2 = 2

    => n3 - 3n2 = 0 

    <=> n2(n - 3) = 0

    According to the topic, n should be positive n = 3

  • ...
    Lê Nho Khoa 23/03/2017 at 21:01

    Have: n3 - 3n2 + 2 = n3 - n2 - 2n2 + 2

    = n2(n - 1) - 2n2 + 2

    It is easy to see that n2(n - 1) is an even number because it contains n(n - 1) which is the product of two consecutive natural numbers, so n2(n - 1) - 2n2 + 2 is an even number

    But n3 - 3n2 + 2 = n2(n - 1) - 2n2 + 2 is a prime number so n3 - 3n2 + 2 = 2

    => n3 - 3n2 = 0 

    <=> n2(n - 3) = 0

    According to the topic, n should be positive n = 

  • ...
    Aomike 22/03/2017 at 21:15

    Have: n3 - 3n2 + 2 = n3 - n2 - 2n2 + 2

    = n2(n - 1) - 2n2 + 2

    It is easy to see that n2(n - 1) is an even number because it contains n(n - 1) which is the product of two consecutive natural numbers, so n2(n - 1) - 2n2 + 2 is an even number

    But n3 - 3n2 + 2 = n2(n - 1) - 2n2 + 2 is a prime number so n3 - 3n2 + 2 = 2

    => n3 - 3n2 = 0 

    <=> n2(n - 3) = 0

    According to the topic, n should be positive n = 3


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Summer Clouds moderators
28/06/2017 at 08:57
Answers
1
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Calculate: \(\dfrac{1}{1+\sqrt{2}}+\dfrac{1}{\sqrt{2}+\sqrt{3}}+....+\dfrac{1}{\sqrt{99}+\sqrt{100}}\).

  • ...
    Phan Thanh Tinh Coordinator 28/06/2017 at 10:34

    Let A be the sum,then :

    \(-A=\dfrac{-1}{1+\sqrt{2}}+\dfrac{-1}{\sqrt{2}+\sqrt{3}}+...+\dfrac{-1}{\sqrt{98}+\sqrt{99}}+\dfrac{-1}{\sqrt{99}+\sqrt{100}}\)

    With \(n\ge0\),we have :

    \(\left(\sqrt{n}+\sqrt{n+1}\right)\left(\sqrt{n+1}-\sqrt{n}\right)=\left(n+1\right)-n=1\)

    \(\Rightarrow\dfrac{1}{\sqrt{n}+\sqrt{n+1}}=\sqrt{n+1}-\sqrt{n}\)

    \(\Rightarrow\dfrac{-1}{\sqrt{n}+\sqrt{n+1}}=\sqrt{n}-\sqrt{n+1}\)

    Hence,we have :

    \(-A=1-\sqrt{2}+\sqrt{2}-\sqrt{3}+...+\sqrt{98}-\sqrt{99}+\sqrt{99}-\sqrt{100}\)

    \(=1-10=-9\)

    \(\Rightarrow A=9\)

    Selected by MathYouLike

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Summer Clouds moderators
30/08/2017 at 08:38
Answers
2
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. Aron, Bern and Carl always lie. Each of them owns one stone, either a red stone or a green stone. Aron says: "My stone is the same color as Bern's stone.'' Bern says: "My stone is the same color as Carl's stone.'' Carl says: "Exactly two of us own red stones.'' Which of the following statements is true?
(A) Aron's stone is green.              (B) Bern's stone is green.            (C) Carl's stone is red.
(D) Aron's stone and Carl's stone have different colors
(E) None of A, B, C or D is true. 

  • ...
    Lê Quốc Trần Anh Coordinator 30/08/2017 at 12:53

    Because they always lie, then:

    - Aron's stone and Bern's stone isn't the same color.

    - Bern's stone and Carl's stone isn't the same color.

    => Aron's stone and Carl's stone is the same color.

    - Exactly two of them own green stones

    => Aron's stone's and Carl's stone's color is green

    => Bern's stone color is red

    So A is the correct answer. (Aron's stone is green)

    Selected by MathYouLike
  • ...
    Phan Thanh Tinh Coordinator 30/08/2017 at 12:51

    Since they always lie, we deduce that Aron's stone is the different color from Bern's stone ; Bern's stone is the diferent color from Carl's stone. So, the colors of Aron's and Carl's are the same and different from the color of Bern's. However, exactly 1 of them owns red stones (or exactly two of them own green stones). So, Aron's and Carl's are green ; Bern's is red.

    Hence, the answer is (A)


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Lê Quốc Trần Anh Coordinator
15/10/2017 at 17:01
Answers
0
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Prove that:

\(\sqrt{15}\) is an irrational number.

\(5-\sqrt{2}\) is an irrational number.

(P/s: solve in 2 ways)


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Cloud moderators
30/11/2017 at 13:53
Answers
1
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Oberon and Lance sit directly opposite each other at a large round table. Arthur sits at the same table, 20 feet from Oberon and 21 feet from Lance. What is the diameter of the table? 

  • ...
    Lê Quốc Trần Anh Coordinator 30/11/2017 at 18:02

    The diameter of the table is: \(\sqrt{20^2+21^2}=\sqrt{400+441}=\sqrt{841}=29\left(ft\right)\)

    Selected by MathYouLike

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FC Alan Walker
08/04/2018 at 03:46
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0
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Prove that:

  1. \(2\dfrac{5}{9}< \dfrac{5}{3}+\dfrac{8}{3^2}+\dfrac{11}{3^3}+...+\dfrac{302}{3^{100}}< 3\dfrac{1}{2}\)

  2. \(3\dfrac{7}{9}< \dfrac{7}{3}+\dfrac{13}{3^2}+\dfrac{19}{3^3}+...+\dfrac{601}{3^{100}}< 5\)

  3. \(\dfrac{11}{3}+\dfrac{17}{3^2}+\dfrac{23}{3^3}+...+\dfrac{605}{3^{100}}< 7\)

  4. \(\dfrac{4}{3}+\dfrac{13}{3^2}+\dfrac{22}{3^3}+...+\dfrac{904}{3^{101}}< \dfrac{17}{4}\)

  5. \(\dfrac{7}{3}+\dfrac{11}{3^2}+\dfrac{15}{3^3}+...+\dfrac{403}{3^{100}}< 4,5\)

Quickly, please. :v


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Lê Quốc Trần Anh Coordinator
12/06/2018 at 11:42
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Given \(\Delta ABC\), bisectris AD, point E and F in AD so that \(\widehat{ABE}=\widehat{CBF}\). Prove that: \(\widehat{ACE}=\widehat{BCF}\)


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Huỳnh Anh Phương
09/07/2018 at 03:42
Answers
1
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Let @a#b@ is the value of \(\left(a+8\right)\times\left(6-b\right)\). For example , @2#6@ = ( 2 + 8 ) x ( 6 - 6 ) = 10 x 0 = 0. Find the value of @8#3@ ? 

  • ...
    Kaya Renger Coordinator 09/07/2018 at 08:24

    @8#3@ = (8 + 8) x (6 - 3) = 16 x 3 = 48

    Huỳnh Anh Phương selected this answer.

...
Hello
03/08/2018 at 14:34
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1
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What baby wings thin funeral
High bay flying low reported that sunshine rain?
What is the child?

  • ...
    Cristiano Ronaldo 03/08/2018 at 14:36

    What baby wings thin funeral
    High bay flying low reported that sunshine rain?
    What is the child?

    Answer: It's a dragonfly


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Koroshimasu
20/07/2017 at 07:42
Answers
2
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I'm a new member, i hope everybody will help me !!! ^ ^
 

  • ...
    triệu lệ dĩnh 20/07/2017 at 10:11


    Oh, yes, welcome to mathyou.com

    Post english problems, we will help you
     

    Koroshimasu selected this answer.
  • ...
    Koroshimasu 20/07/2017 at 15:23

    thank you so much hihi


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Trigonometric
sin cos tan cot sinh cosh tanh
Lim-log

Combined operations

 

α β γ δ θ σ ∂ ε ω φ ϕ π μ λ Ψ ξ η χ ζ ι κ ν ψ Ω ρ τ υ Γ Δ Λ Φ Π Σ Υ Ξ ϑ Θ ς ϰ
∞ ⊻ ⩞ ⋎ ⋏ ≀ ∪ ⊎ ⋓ ∩ ⋒ ⊔ ⊓ ⨿ ⊗ ⊙ ⊚ ⊛ ⊘ ⊝ ⊕ ⊖ ⊠ ◯ ⊥
⇔ ⇒ ⇐ → ← ↔ ↑ ↓
Operations
+ - ÷ × ≠ = ⊂ ⊃ ⊆ ⊇ ≈ ∈ ∉ ∃ ∄ ≤ ≥ ± ∓ ≠ ∅ ≃ ≅ ≡ ⋮ ⋮̸ ∀
(□) [□] {□} |□|

The type of system

m×n 1×2 1×3 1×4 1×5 1×6
2×1 2×2 2×3 2×4 2×5 2×6
3×1 3×2 3×3 3×4 3×5 3×6
4×1 4×2 4×3 4×4 4×5 4×6
5×1 5×2 5×3 5×4 5×5 5×6
6×1 6×2 6×3 6×4 6×5 6×6

Recipe:

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Crafted with by HCEM