The probability that the coin lands head up is: \(1:2=\dfrac{1}{2}\)

The probability that the die rolls as a prime number from 1-6 (The numbers are: 4): \(1:6=\dfrac{1}{6}\)

So their probability are: \(\dfrac{1}{2}.\dfrac{1}{6}=\dfrac{1}{12}\)

\(\dfrac{x-2}{9}=\dfrac{4}{x-2}\)

<=> \(\left(x-2\right)\left(x-2\right)=4.9\)

<=> \(\left(x-2\right)^2=36\)

<=> \(x-2=\sqrt{36}\)

<=> \(x-2=6\) <=> \(x=6-2=4\)

b, 2,5:x=1,5:12

    2,5:x=0,125

    x = 2,5:0,125

    x = 20

d, \(\dfrac{x}{6}=\dfrac{24}{25x}\) => \(x.25x=6.24\) => \(x^2.25=144\) <=> \(x^2=144:25=5,76\)<=> \(x=\sqrt{5,76}=2,4\)

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You could go to this source for Vietnamese question: https://olm.vn/

You could go to this source for Vietnamese question: https://olm.vn/

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P/s: Vietnamese is permitted in Mathu.

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Source: https://sites.google.com/site/toanhoctoantap/chuyen-dhe-toan-hoc/tim-chu

2: Every exponential in the equation that the index number :4 have the remainder 1. So that every exponential in the equation has the same ending number, equals to:

\(\left(2+3+4+...+9\right)+199.\left(1+2+...+9\right)+1+2+3+4=9009.\)

So the last number of it is: 9

I have a question: Is a,b \(\in Z\)?

Kayasari Ryuunosuke, why can \(\sqrt{32}=6\)? The solution is not correct.

The largest number in B satisfy the question is: \(10\)

The largest number in C satisfy the question is: \(11\)

We see: 10 < 11

So the answer of the question is: \(11\)

The individual price of 10 rides is: \(15+2,50=17,50\)

So the answer is: \(17,50\)

The width of the rectangle is: \(18:\dfrac{9}{4}=8\left(cm\right)\)

So it's width is 8cm.

The total time from home-movie theater, duration of the movie to movie theater-home is:

\(15minutes+10minutes+1hour43minutes+25minutes=2hours33minutes\left(2:33\right)\)

He get home at: \(4:05+2:33=6:38\left(pm\right)\)

So he got home at 6:38 pm.

x + y = 7 and x - y = 1.

=> x = 4 and y = 3.

=> The product of x.y is: \(4.3=12\)

So the answer is: \(12\)

The ratio of gummies to peppermints is: 3:4

The ratio of chocolates to peppermints is: 3:5

So the ratio of chocolates to gummies is: \(\dfrac{3}{4}.\dfrac{3}{5}=\dfrac{9}{20}\) (9:20)

There is 3 activities in the competition is: +3 marks, -2 marks and -1 marks.

So there must be: \(\left(10.3\right).4=120\left(students\right)\)taken the test to satisfy the question.

The area of the circle is: \(2^2.3,14=12,56\left(cm^2\right)\)

Because the shaded part has the area equals to each other and in the figure => The rectangle's area is 1/2 the area of the circle (2.1/4=1/2)

So the area of the rectangle is: \(12,56.\dfrac{1}{2}=6,28\left(cm^2\right)\)

From the figure, the width of the. rectangle = the radius of the circle => The width of the rectangle is \(2cm\). So the side AB = \(6,28:2=3,14\left(cm\right)\)

So the answer is: \(3,14cm\)

The numbers that satisfy the operation is: \(2;3;4;5;6\)

So their product is: \(2.3.4.5.6=720\)