Ok, I agree.

Oh, I'm wrong. My solution is: 4.3.2 (not 3.3.2). Thanks Phan Thanh Tinh for your answer.

Sorry, but I calculate again with my computer, and the result is: 75,36 cubic inches. That's my idea.

Convert: 1 foot = 12 inches, 12 feet by 13 feet = 144 inches by 156 inches.

The total area of 10 tiles (bought in 1 box) is: \(\left(6.6\right).10=360\left(cubic-inches\right)\)

The area of the floor is: \(144.156=22464\left(cubic-inches\right)\)

The box that must bought is: \(22464:360=62,4\left(box\right)\)

So the minimum number of boxes must be purchased is: \(63boxes\)

The area of the label is: \(\left(4:2\right)^2\pi.6=75,36\left(cubic-inches\right)\)

So the area of the label is: \(75,36cubic-inches\)

The total money of 3 person is: \(53.3=159\left(million\right)\)

The taxes of 1 person is: \(\left(234-159\right):3=25\left(millions\right)\)

The total of the money of 1 person: \(25+53=78\left(million\right)\)

The percentage of the tax of 1 person is: \(25:78\simeq0,3205\simeq32,05\%\)

We see: \(4triangles=1big-square.\)

The area of the big square is: \(\left(1:2\right).4=2\left(square-unit\right)\).

So the answer is: \(2square-unit.\)

P/s: This question is asked before.

The number of people were selected to be contestants is: \(3000000.\left(1\%.1\%\right)=3000000.\left(0.01\%\right)=300\left(people\right)\)

So the answer is: \(300people\)

Convert: 1 foot = 12 inches, 5 feet 6 inches = 66 inches.

If a human were able to jump, an American will be able to jump: \(66.350=23100\left(inches\right)=1925\left(feet\right)\)

Call the digits of the mobile device: abcd \(\left(a\ne b\ne c\ne d\right)\) and \(a,b,c,d\in\left\{0;1;2;...;9\right\}\)

So there'll be: \(3.3.2=18\left(ways\right)\)for the number abcd in random order.

So the probability is: \(\dfrac{1}{18}\simeq5,56\%\)

A diference date only appears once/month (Only 1 subtraction is classified). So there will be: 1 difference date/month -> 12 difference date/ year -> 1200 difference date/ century.

So there will be 1200 difference date during the 21st century.

The sum of the cost and the tax is: \(100\%+8\%=108\%\left(=133,38\right)\)

The cost of the software is: \(133,38:108\%.100\%=123,5\left(dollars\right)\)

The male panda at the local zoo weighs: \(49,35:15\%=49,35:\dfrac{15}{100}=329\left(pounds\right)\)

So the answer is: \(329pounds\)

The side of a small square is: \(12:4=3\left(cm\right)\)

A line has: \(12:3=4\left(square\right)\)

So the perimeter of the big rectangle is: \(\left(3.4\right).2+\left(3.3\right).2=42\left(cm\right)\)

So the answer is: D

Sorry because I missunderstood the question.

The fraction of the question is: \(1-\left(\dfrac{1}{2}.\dfrac{1}{2}\right)=\dfrac{3}{4}\)

There are: \(300-28=272\left(members\right)\)not in Mr.Jackson's Algebra 1 class. 

The probability that the first student is chosen not from Mr.Jackson's Algebra 1 class is: \(272:300=\dfrac{272}{300}\)

The robability that the second student is chosen not from Mr.Jackson's Algebra 1 class is: \(\dfrac{272-1}{300-1}=\dfrac{271}{299}\)

So the probability that neither of the students selected will be from Mr.Jackson's Algebra 1 class is:

\(\dfrac{272}{300}.\dfrac{271}{299}=0,8217....\simeq82,17\%\)

Thanks Phan Thanh Tinh for your answer. I'll read the questions carefully the other time.

The area of the small circle is: \(x.x.3,14=x^2.3,14\)

The area of the bigger circle is: \(3x.3x.3,14=9x^2.3,14\)

So the fraction is: \(\dfrac{x^2.3,14}{9x^2.3,14}=\dfrac{1}{9}\)

Convert: 1,75m=175cm

The greatest number of segments each 10cm is: \(175:10=17,5\left(segments\right)\)

So the greatest number of segments is: 17 segments.

There are 12 hours in the analog clock => 6 hours in the upper half.

There are 60 minutes in the analog clock => 30 minutes in the upper half.

So the fraction is: \(\dfrac{6}{30}=\dfrac{1}{5}\)