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Help you solve math 16/08/2017 at 15:02We have:
8^20=(2^3)^20=2^80
=>8^20=2^80
phanhuytien selected this answer.
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Lê Quốc Trần Anh Coordinator
30/08/2017 at 16:55
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Dao Trong Luan 30/08/2017 at 17:33\(\dfrac{81^4\cdot3^{10}\cdot27^5:3^{12}}{3^{18}:9^3\cdot243^2}=\dfrac{\left(3^4\right)^4\cdot3^{10}\cdot\left(3^3\right)^5:3^{12}}{3^{18}:\left(3^2\right)^3\cdot\left(3^5\right)^2}\)
\(=\dfrac{3^{16}\cdot3^{10}\cdot3^{15}:3^{12}}{3^{18}:3^6\cdot3^{10}}=\dfrac{3^{16+10+15-12}}{3^{18-6+10}}=\dfrac{3^{29}}{3^{22}}=3^7=2187\)
Lê Quốc Trần Anh selected this answer. -
FA KAKALOTS 08/02/2018 at 22:00814⋅310⋅275:312318:93⋅2432=(34)4⋅310⋅(33)5:312318:(32)3⋅(35)2
=316⋅310⋅315:312318:36⋅310=316+10+15−12318−6+10=329322=37=2187
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The number of 1-digit numbers is : (9 - 1) + 1 = 9
The number of 2-digit numbers is : (99 - 10) + 1 = 90
The number of 3-digit numbers is : (321 - 100) + 1 = 222
The number of digits she wrote is :
9 x 1 + 90 x 2 + 222 x 3 = 855
Selected by MathYouLike -
Vũ Trung Dũng 18/09/2017 at 05:53The number of 1-digit numbers is : (9 - 1) + 1 = 9
The number of 2-digit numbers is : (99 - 10) + 1 = 90
The number of 3-digit numbers is : (321 - 100) + 1 = 222
The number of digits she wrote is :
9 x 1 + 90 x 2 + 222 x 3 = 855
Answer : 855
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→இے๖ۣۜBoy™†hïếuGîa 16/09/2017 at 13:39
he number of 1-digit numbers is : (9 - 1) + 1 = 9
The number of 2-digit numbers is : (99 - 10) + 1 = 90
The number of 3-digit numbers is : (321 - 100) + 1 = 222
The number of digits she wrote is :
9 x 1 + 90 x 2 + 222 x 3 = 855
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Lightning Farron 01/01/2018 at 21:28By Cauchy-Schwarz's ineq:
\(VP=\dfrac{4a^2}{2ab+2ac}+\dfrac{4b^2}{2ab+2bc}+\dfrac{4c^2}{2ac+2bc}\)
\(\ge\dfrac{\left(2a+2b+2c\right)^2}{4\left(a+b+c\right)}=\dfrac{4\left(a+b+c\right)^2}{4\left(a+b+c\right)}=a+b+c=VT\)
When \(a=b=c=1 \Rightarrow A=3\)
Alone selected this answer. -
FA Liên Quân Garena 08/01/2018 at 21:58
By Cauchy-Schwarz's ineq:
VP=4a22ab+2ac+4b22ab+2bc+4c22ac+2bc
≥(2a+2b+2c)24(a+b+c)=4(a+b+c)24(a+b+c)=a+b+c=VT
When a=b=c=1⇒A=3
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Alone 13/06/2018 at 10:11We have:\(a+\dfrac{1}{b}+b+\dfrac{1}{c}+c+\dfrac{1}{a}< 6\)
But \(a+\dfrac{1}{a}+b+\dfrac{1}{b}+c+\dfrac{1}{c}\ge2\sqrt{a.\dfrac{1}{a}}+2\sqrt{b.\dfrac{1}{b}}+2\sqrt{c.\dfrac{1}{c}}=2+2+2=6\)
So there are no a,b,c>0 satisfys
Lê Quốc Trần Anh selected this answer.
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Cristiano Ronaldo 04/08/2018 at 01:26
In the same year he lived in a house
Parenting in the harmony
The old man was three
An old man was two years old.
What is the trick?Answer: It's five finger
Bookname selected this answer.
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\(2+4+6+....+996+998+1000\)
\(=2\times\left(1+2+3+...+498+499+500\right)\)
\(=2\times\dfrac{500\times501}{2}=250500\)
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NGUYỄN SANH KIÊN 04/07/2017 at 07:07SUPER SAIYAN GOKU copy is not good
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Super Saiyan Goku 30/06/2017 at 11:40\(2+4+6+...+996+998+1000\)
\(=2\times\left(1+2+3+...+498+499+500\right)\)
\(=2\times\dfrac{500\times501}{2}=250500\)
Ai mk,mk lại!
