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ღ kekio ღ 21/07/2017 at 08:30
a, consider the triangle AHFK: \(\widehat{A}=\widehat{H}=\widehat{K}=90^o\)
should AHFK is rectangle
b, consider the triangle ACF :OA=OC;EC=EF
should OE is the average line of the triangle ACF
should OE//AF or AF//BD
similar: the average line is EJ triangle ACF
should EJ//ACsimilar: the average line is EJ triangle ACF
should EJ//AC\(\Rightarrow\widehat{AKJ}=\widehat{KAJ}+\widehat{KAJ}=\widehat{KDE}\)pairs of isotopes
\(\Rightarrow\widehat{AKJ}=\widehat{KDE}\) or KDE loss triangle
inferred :\(\widehat{JK}=\widehat{DEK}=\dfrac{180-KDE}{2}\) should K; J and E line
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that K; J; H line
should K; H and E also in line and HK//AC -
ღ kekio ღ 21/07/2017 at 08:06
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Sorry, can I fix the answer?
The probability of the die shows a prime number from 1-6 (The numbers: 2;3;5): \(1:2=\dfrac{1}{2}\)
So their probability are: \(\dfrac{1}{2}.\dfrac{1}{2}=\dfrac{1}{4}=25\%\)
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The probability that the coin lands head up is: \(1:2=\dfrac{1}{2}\)
The probability that the die rolls as a prime number from 1-6 (The numbers are: 4): \(1:6=\dfrac{1}{6}\)
So their probability are: \(\dfrac{1}{2}.\dfrac{1}{6}=\dfrac{1}{12}\)
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Let n be the number of edges of the polygon \(\left(n\in N;n>2\right)\)
We have : \(180\left(n-2\right)=1260\Leftrightarrow n-2=7\Leftrightarrow n=9\)
So, the polygon has 9 sides.
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Vũ Trung Dũng 21/09/2017 at 14:42
Let n be the of edges of the polygon and (n ∈ N, n > 2)
We have :
180 . (n - 2) = 1260 <=> n - 2 = 7 => n = 9
Answer: 9 sides
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Help you solve math 29/08/2017 at 17:01
Let n be the of edges of the polygon and (n ∈ N, n > 2)
We have :
180 . (n - 2) = 1260 <=> n - 2 = 7 => n = 9
Answer: 9 sides
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The first reflection changes P(-3 ; -2) to (2 ; 3). The answer is :
(2 + 4 ; 3 - 1) = (6 ; 2)
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Math You Like 14/09/2017 at 16:14
The first reflection changes P(-3; -2) to (2; 3)
The answer is:
(2 + 4; 3 - 1) = (6; 2)
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Let a, b be the price of an oldies CD and a current CD respectively.
We have :
(2a + 3b) - (3a + 2b) = 82 - 78 <=> b - a = 4
So, the answer is 4
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Let a, a + 1, a + 2, ... , a + 10 be the integers. We have :
\(a+\left(a+1\right)+\left(a+2\right)+...+\left(a+10\right)=11\)
\(\Leftrightarrow11a+\dfrac{10.11}{2}=11\Leftrightarrow a+\dfrac{10}{2}=1\Leftrightarrow a=-4\)
So, the answer is -4
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Help you solve math 31/12/2017 at 08:40
P/s Mk chỉ biết 45777 > 35674 vì dễ thấy mà mk cũng không biết cách trả lời
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Help you solve math 01/01/2018 at 10:58
Bạn là người copy câu trả lời của Đào Trọng luân
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Nguyễn Huy Thắng 24/04/2018 at 10:15
\(Q=\dfrac{3\left(x+1\right)}{x^3+x^2+x+1}=\dfrac{3\left(x+1\right)}{\left(x+1\right)\left(x^2+1\right)}=\dfrac{3}{x^2+1}\)
We have: \(x^2\ge0\forall x\Leftrightarrow x^2+1\ge1\forall x\)
\(\Leftrightarrow\dfrac{1}{x^2+1}\le1\forall x\)
\(\Leftrightarrow Q=\dfrac{3}{x^2+1}\le3\forall x\)
\("="\Leftrightarrow x=0\)