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Answers ( 23 )
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    Call Alice's age: a

            Betty's age: b

            Clara's age: c

        (a,b,c\(\in\)N*)

    According to the theme we have:
    \(a+b+c=29\)(1)

    \(b-a=4\Rightarrow b=a+4\)(2)

    \(c-b=6\Rightarrow c=b+6\Rightarrow c=a+4+6=a+10\)(3)

    Change (2)(3) to (1) we have:
    \(\left(1\right)\Leftrightarrow a+b+c=29\)

    \(a+a+4+a+10=29\)

    \(3a+14=29\)

    \(3a=29-14=15\)

    \(a=5\)(satisfy)

    Alice's age: 5 years old

  • See question detail

    The height of Paul:

    \(\left(94+8\right):2=51\left(inches\right)\)

    The height of Rachel:

    \(51-8=43\left(inches\right)\)

  • See question detail

    \(\left(5\dfrac{1}{3}-2\dfrac{1}{2}\right)+\left(5\dfrac{1}{2}-3\dfrac{1}{3}\right)\)

    \(=5\dfrac{1}{3}-2\dfrac{1}{2}+5\dfrac{1}{2}-3\dfrac{1}{3}\)

    \(=\left(5\dfrac{1}{3}-3\dfrac{1}{3}\right)-\left(2\dfrac{1}{2}-5\dfrac{1}{2}\right)\)

    \(=2\dfrac{1}{3}-\left(-3\dfrac{1}{2}\right)=2\dfrac{1}{3}+3\dfrac{1}{2}=5\dfrac{5}{6}\)

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