-
See question detail
We have 3432 = 23 x 3 x 11 x 13
5460 = 22 x 3 x 5 x 7 x 13
=> GCD (3432 ; 5460) = 22 x 3 x 13 = 156
-
See question detail
1998 = 2 x 33 x 37,then 1998 has : (1 + 1)(3 + 1)(1 + 1) = 16 (factors)
So x = 16
P/S : 16 is the number of positive factors of 1998,so 1998 has 32 integer factors
-
See question detail
The odd number between the six remaining numbers is:
1337 : 7 = 191
So 7 consecutive numbers are 185 ; 187 ; 189 ; 191 ; 193 ; 195 ; 197
-
See question detail
b3 = 3375 = 153 => b = 15 => a = 13 ; c = 17 => ac = 221
1
-
See question detail
The distance between the houses is: 3000: 100 = 30 (minute)
Homeownership is: 3000: 150 = 20 (minutes)
Average by John in a minute: 3000: (20 + 30) = 60 (minute)Answers:60 minute
-
See question detail
The distance between the houses is: 3000: 100 = 30 (minute)
Homeownership is: 3000: 150 = 20 (minutes)
Average by John in a minute: 3000: (20 + 30) = 60 (minute)Answers:60 minute
-
See question detail
Love people Name Jiang 23 hour before (20:09)
Numbers sweet is the biggest that he can get from the shop is :
30 : 3 = 10 (sweet)
Answer : 10 sweet
-
See question detail
Number of female is : 60 x 3 : 5 = 36 ( student )
Number of male is : 60 - 36 = 24 ( student )
Answer : 24 student
-
See question detail
The edge length of the cube is :
3√2162163 = 6 (cm) because 6 x 6 x 6 = 216
The area is :
6 x 6 = 36 (cm2)
-
See question detail
Change : half an hour = 0,5 hour
The speed of the car is :
( 25 - 5 ) : 0,5 = 40 ( km / hour )
Answer : 40 km / hour
-
See question detail
Change : half an hour = 0,5 hour
The speed of the car is :
( 25 - 5 ) : 0,5 = 40 ( km / hour )
Answer : 40 km / hour
-
See question detail
a) 19:14=1514
b) 28:13=2213
c) 27:21= 127
d) 15:10=112
e) 45:6=712
-
See question detail
a) 19:14=
1514
b) 28:13=2213
c) 27:21= 127
d) 15:10=112
e) 45:6=712
-
See question detail
a) Five fractions equals 3/5: 6/10; 9/15; 12/20; 15/25; 30/50.
b) Five fractions equals 5/8: 10/16; 15/24; 20/32; 25/40; 50/80.
c) Five fractions equals 36/108: 1/3; 2/6; 3/9; 12/36; 18/54.
-
See question detail
We have :
2a+b+c+da=a+2b+c+db=a+b+2c+dc=a+b+c+2dd
⇒2a+b+c+da−1=a+2b+c+db−1=a+b+2c+dc−1=a+b+c+2dd−1
⇒a+b+c+da=a+b+c+db=a+b+c+dc=a+b+c+dd