We have: 

⇒a=2017n−2016b⇒a=2017n−2016b

We have: 2a+2015b=2(2017n−2016b)+2015b=2.2017n−2017b⋮2017

We have: 

⇒a=2017n−2016b⇒a=2017n−2016b

We have: 2a+2015b=2(2017n−2016b)+2015b=2.2017n−2017b⋮20172a+2015b=2(2017n−2016b)+2015b=2.2017n−2017b⋮2017

Same as above. We hava: ⎧⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎨⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎩3a+2014b=3.2017n−2.2017b⋮20174a+2013b=4.2017n−3.2017b⋮2017...2015a+2b=2015.2017n−2014.2017b{3a+2014b=3.2017n−2.2017b⋮20174a+2013b=4.2017n−3.2017b⋮2017...2015a+2b=2015.2017n−2014.2017b

So that: A⋮2017.2017...2017A⋮2017.2017...2017

⇒A⋮20172014

We have : x < -0.8 ⇒ x + 0,8 < 0 ⇒|x + 0.8| = -(x + 0.8)

                 x < -0.8 ⇒ x < 25 ⇒ |x - 25| = 25 - x

Candle A = -(x + 0.8) - (25 - x) + 1.9

                = -x + 0,8 - 25 + x + 1,9

                = -x + x - 0,8 - 25 + 1,9

                = -25,8 + 1,9

            A = -23,8

     A = -x - 0.8 - 25 + x + 1.9

     A = -23.9 

a) With 2x + 3 = x + 2

=> 2x - x = 2 - 3

=> x = -1

With 2x + 3 = -(x + 2)

=> 2x + 3 = -x - 2

=> 2x + x = -2 - 3

=> 3x = -5

=> x = −53

So x = -1 and x = −53

b) We have : 

A = |x - 2006| + |2007 - x| ≥ |x - 2006 + 2007 - x| = |1| = 1

⇔{|x−2006|≤0|2007−x|≤0⇒{x=2006x=2007

So when x = 2006 ; 2007 then value of A smallest 

We have : (x + 2)(x + 2) = 24(x + 2)(x + 2) = 24

⇒x2 + 4x + 4 =24

=> x2 + 4x = 20

=> x(x + 4) = 20

=> x ,x + 4 thuộc Ư(20) = {1;2;4;5;10;20}

 When x = 1 thì x + 4 = 20 => x = 16 

Not yes value satisfies

Number of female students is :

  40 x \(\dfrac{2}{5}\)= 16 ( student )

Number of male students is :

   40 - 16 = 24 ( student )

      Answer : 24 student

Number of terms is :

  ( 1000 - 1 ) : 2 + 1 = 500,5 

The sum is :

  ( 1000 + 1 ) x 500,5 : 2 = 250500,25

You have:

(x+1).(1+1999)=4000

(x+1).2000=4000

x+1=4000:2000

x+1=2

x=2-1

x=1

You have abcabc=abc.1001

                           =abc.91.11

Thus,abcabc is divisible by 11.

You have:300=2².3.5²

The number of integer factors 300 have is:

\(2.[\left(2+1\right).\left(1+1\right).\left(2+1\right)]=36\)

Answer:36.

100 + 500:5-40

=100+100-40

=200-40

=160

\(\dfrac{5}{8}+\dfrac{9}{8}=\dfrac{5+9}{8}=\dfrac{14}{8}=\dfrac{7}{4}\)

\(\dfrac{6}{7}-\dfrac{3}{7}=\dfrac{6-3}{7}=\dfrac{3}{7}\)