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We have : x + 2x + 4x+ 8x + 16x +32x = 12345
<=> x(2 + 4 + 8 + 16 + 32) = 12345
<=> 62x = 1234
=> x = ////////////////////
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We have : 5x2y + 4xy - 9x2y - 4xy
= 5x2y - 9x2y + 4xy - 4xy
= -4x2y
Good
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Can not believe someone z
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You see you to you to your coppy
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Immerse yourself in the equality of the score
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No 2017 yes 2007
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No Kurosaki Akatsu I do not do not copy your articles do not shamelessly z look back . You Is answering that wrong
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Kurosaki Akatsu and Love the Name of Jiang good
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Kurosaki Akatsu good .
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We have \(\dfrac{a}{b}=\dfrac{b}{c}=\dfrac{c}{a}=\dfrac{a+b+c}{b+c+a}=1\)
Then : \(\dfrac{a}{b}=1\Rightarrow a=b\)
\(\dfrac{b}{c}=1\Rightarrow b=c\)
\(\dfrac{c}{a}=1\Rightarrow c=a\)
Deduced : a = b = c
Which top post for a + b + c = 2007 => 3a = 2007 => a = 2007 : 3 = 669
Dress a = b = c = 669
There is something to ask good because neck one question or
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Kurosaki Akatsu thanks so much
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Kurosaki Akatsu The solution is good
The total velocity of the two vehicles is:
(40 + 45) = 85 (km/giờ)
The long AB distance is:
85 x 3 = 255 (km)
Answer : 255 km
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Uneykers Greet the whole question well :
We have : H - G = (5x2y - 7xy + 3xy2 - 5) - (5xy + xy2 - 6x2y + 9)
= 5x2y - 7xy + 3xy2 - 5 - 5xy - xy2 + 6x2y - 9
= 5x2y + 6x2y - 7xy - 5xy + 3xy2 - xy2 - 5 - 9
H - G = 11x2y - 12xy + 2xy2 - 14
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Look at the chart you see .
Mary eat the least orange then Mary can eat one orange
Jack ate the most orange then Jack can eat 6 orange
Jack eat more Mary than the orange is:
6 - 1 = 5 (orange)
Answer : 5 orange
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We have -G - M = -(4xy - 3x2y + 3xy2 - 7) - (3x2y + 2xy - 2xy2 + 4)
= -4xy + 3x2y - 3xy2 + 7 - 3x2y - 2xy + 2xy2 - 4
= -4xy -2xy + 3x2y - 3x2y - 3xy2 + 2xy2 + 7 - 4
= -6xy - xy2 + 3
It is very special when -M - G = -G - M. The math problem is interesting and interesting
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We have : -M - G = -(3x2y + 2xy - 2xy2 + 4) - (4xy - 3x2y + 3xy2 - 7)
= -3x2y - 2xy + 2xy2 - 4 - 4xy + 3x2y - 3xy2 + 7
= -3x2y + 3x2y - 2xy - 4xy + 2xy2 - 3xy2 - 4 + 7
= -6xy - xy2 + 3
Peace of mind 100%
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Math You Unfair Because i answer that before
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We have : A = 1.2 + 2.3 + 3.4 + ...... + 1999.2001
=> 3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ...... + 1999.2001.2002
=> 3A = 1999.2001.2002
=> A = 1999.2001.2002/3
=> A = 2 666 666 000
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The sum of the sums of the above sum is :
(104 - 2) : 3 + 1 = 35 (skull)
The sum above is :
(104 + 2) x 35 : 2 = 1855
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The sum of the sums of the above sum is:
(1999 - 1) : 2 + 1 = 1000 (skull)
The sum above is:
(1999 + 1) x 1000 : 2 = 1 000 000