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Answers ( 160 )
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    We have : 37 = 3 + 5 + 29 (c1)

                     37 = 3 + 11 + 23 (c2)

                     37 = 5 + 13 + 19 (c3)

    Drees is three ways are there to write 37 

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    We have : 100 + 500 : 5 - 40 

    = 100 + 100 - 40

    = 200 - 40

    = 160 

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    We have: abcdeg = abc000 + deg
    = Abc. 100000 + deg
    = Abc. 99999 + (abc + deg)
    Which - 99999 is divisible by 37 so abc. 99999 is divisible by 37
    - abc + deg is divisible by 37
    So the distribution is divided by 37 (ddcm)

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    We have : \(\left(1-\dfrac{1}{2}\right)\left(1-\dfrac{1}{3}\right)\left(1-\dfrac{1}{4}\right).......\left(1-\dfrac{1}{2017}\right)\)

    \(=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}......\dfrac{99}{100}\)

    \(=\dfrac{1}{100}\)

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    You have : 300 = 22.3.52

    The number of integer factors 300 have is :

                          2.[(2 + 1)(1 + 1)(2 + 1)] = 36

                                   Answer : 36. good

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    The area around the cube is:
                           A x a x 4 = a x a x 4
    Total cube area is:
                           A x a x 6 = a x a x 6
    The head for the total area larger than the surrounding area is: a x a x 6 - a x a x 4 = 162
    The total area larger than the surrounding area is:
    A x a x (6 - 4) = a x a x 2
    A x a is:
                  162: 2 = 81 (cm2)
    Because 81 = 9 x 9, the edge of the cube is 9 cm
    Cubic volume is:
                  9 x 9 x 9 = 729 (cm3)
                            Answer: 729 cm3

    Good . You Good 

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    We have (n-1)n(n+1)=(n^2-n)(n+1)=(n^2-n)n+n^2-n=n^3-n^2+n^2-n

             =n^3-n

    \Rightarrow n^3=(n-1)n(n+1)+n (1)

    Apply (1) to the expression, we have : 13 + 23 + 33 + ... + 20083 

    = (1 - 1)1(1 + 1) + 1 + (2 - 2)2(2 + 2) + 2 + ....... + (2008 - 2008) 2008 (2008 - 2008) + 2008

    = 1 + 2 + 1.2.3 + 3 + 2.3.4 + ........ + 2008 + 2007.2008.2009

    = (1 + 2 + 3 + ...... + 2008) + (1.2.3 + 2.3.4 + ...... + 2007.2008.2009)

    = 2017036 + 2007.2008.2009.2010 / 4 

    = The number to mik not count 

  • See question detail

    You have : 300 = 220,30,52

    The number of integer factors 300 have is :

                          2.[(2 + 1)(1 + 1)(2 + 1)] = 36

                                   Answer : 36. good

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    We have : ƯCLN(140;240) = 20

    Dress the largest square can be 20 cm x 20 cm

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    I have : abcabc = abc x 1001

                             = abc x 91 x 11

    Ghost abc \(\in\) N Candle abcabc divisible by 11 

    Good

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    I have the recipe is

    n(n + 2) = (n + 1)2 - 1 

     
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    We have : ab = 8(a + b) 

    => 10a + b = 8a + 8b

    => 10a - 8a = 8b - b

    => 2a = 7b

    => a = 7 ; b = 2

    So ab is 72

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    BCNN (a,b) = 50 => a,b = 25;50 . 10;50 . 1;50 . 2;50 . 5;50 

    Good  

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    Volume Min block is : 

                  11.3.2 = 66 (in3)

                      Answer : 66 in3

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    Replacing x = 1/2 we have: 4x - 3a = 0  

    <=> 4.1/2 - 3a = 0

    => 2 - 3a = 0

    => 3a = 2

    => a = 2/3

    Dress a = 2/3 good

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    For : \(A=\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{32}+\dfrac{1}{64}+\dfrac{1}{128}\)

    \(\Rightarrow2A=1+\dfrac{1}{2}+\dfrac{1}{4}+.....+\dfrac{1}{128}\)

    \(\Rightarrow2A-A=1-\dfrac{1}{128}\)

    \(\Rightarrow A=\dfrac{127}{128}\)

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    Ta có : 3 + 32 + 33 + ...... + 32000

    => 3A = 32 + 33 + 34 + ...... + 32001

    => 3A - A = 32001 - 3

    => 2A = 32001 - 3

    => A = \(\dfrac{3^{2001}-3}{2}\)

    Good

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    Hao made the number is:

      236 x 1/3 = ?

    No

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    \(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+.......+\dfrac{1}{999999.1000}\)

    \(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+.......+\dfrac{1}{999}-\dfrac{1}{1000}\)

    \(=1-\dfrac{1}{1000}\)

    \(=\dfrac{999}{1000}\)

  • See question detail

    a, x 3 .x 4 = x7

    b, 15.14=1

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