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Nguyễn Phương Uyên

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2000 Questions
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  • Nguyễn Phương Uyênanswered a question

    07/08/2018 at 06:14

    \(\dfrac{1}{4+\dfrac{1}{4+\dfrac{1}{4+\dfrac{1}{4}}}}\)

    \(=\dfrac{1}{4+\dfrac{1}{4+\dfrac{1}{\dfrac{17}{4}}}}\)

    \(=\dfrac{1}{4+\dfrac{1}{4+1\div\dfrac{17}{4}}}\)

    \(=\dfrac{1}{4+\dfrac{1}{4+\dfrac{4}{17}}}\)

    \(=\dfrac{1}{4+\dfrac{1}{\dfrac{72}{17}}}\)

    \(=\dfrac{1}{4+\dfrac{17}{72}}\)

    \(=\dfrac{1}{\dfrac{140}{17}}\)

    \(=\dfrac{17}{40}\)

  • Nguyễn Phương Uyênanswered a question

    07/08/2018 at 06:11

    \(\dfrac{1}{4\dfrac{3}{7}}+\dfrac{1}{3\dfrac{11}{13}}+\dfrac{1}{\dfrac{5}{9}}\)

    \(=\dfrac{1}{\dfrac{31}{7}}+\dfrac{1}{\dfrac{50}{13}}+\dfrac{1}{\dfrac{5}{9}}\)

    \(=1\div\dfrac{31}{7}+1\div\dfrac{50}{13}+1\div\dfrac{5}{9}\)

    \(=\dfrac{7}{31}+\dfrac{13}{50}+\dfrac{9}{5}\)

    \(=\dfrac{3543}{1550}\)

  • Nguyễn Phương Uyênliked an answer of question

    06/08/2018 at 07:07
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