Quoc Tran Anh Le Coordinator
07/08/2018 at 05:34-
\(\dfrac{1}{4+\dfrac{1}{4+\dfrac{1}{4+\dfrac{1}{4}}}}=\dfrac{1}{4+\dfrac{1}{4+\dfrac{1}{\dfrac{17}{4}}}}=\dfrac{1}{4+\dfrac{1}{4+\dfrac{4}{17}}}=\dfrac{1}{4+\dfrac{1}{\dfrac{72}{17}}}=\dfrac{1}{4+\dfrac{17}{72}}=\dfrac{1}{\dfrac{305}{72}}=\dfrac{72}{305}\)
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Nguyễn Phương Uyên 07/08/2018 at 06:14\(\dfrac{1}{4+\dfrac{1}{4+\dfrac{1}{4+\dfrac{1}{4}}}}\)
\(=\dfrac{1}{4+\dfrac{1}{4+\dfrac{1}{\dfrac{17}{4}}}}\)
\(=\dfrac{1}{4+\dfrac{1}{4+1\div\dfrac{17}{4}}}\)
\(=\dfrac{1}{4+\dfrac{1}{4+\dfrac{4}{17}}}\)
\(=\dfrac{1}{4+\dfrac{1}{\dfrac{72}{17}}}\)
\(=\dfrac{1}{4+\dfrac{17}{72}}\)
\(=\dfrac{1}{\dfrac{140}{17}}\)
\(=\dfrac{17}{40}\)