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Answers ( 3 )
  • See question detail

    Call the bigger numbers a, the smaller number b

    We have: a-b=6 and a+b=24

    => a-b+a+b=6+24

    =>2a=30

    =>a=30:2

    =>a=15

    => 15-b=6

    =>b=9

    So the products of the two numbers are 15 and 9

  • See question detail

    \(0,0A=\sqrt{0.0049}=0.07\)

    \(\Rightarrow A=7\)

  • See question detail

    1+2+3+...+10

    =(1+10)*10:2

    =11*5

    =55

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Questions ( 2 )
  • Give: \(a+b+c\ge abc\).Prove that:

    \(a^2+b^2+c^2\ge abc\)

  • Solve these equations:

    a) \(\dfrac{6}{\left(x+1\right)\left(x+2\right)}+\dfrac{8}{\left(x-1\right)\left(x+4\right)}=1\)

    b)\(\dfrac{x^2-3x+5}{x^2-4x+5}+\dfrac{x^2-5x+5}{x^2-6x+5}=\dfrac{-1}{4}\)

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