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Answers ( 49 )
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     After the preschool fee of $330, Cody paid an additional 770 – 330 = $440 for after-school care. Dividing $440 by the hourly rate of $5.50, we find that Cody’s son must have spent 80 hours in after-school care. 

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     Let n – 1, n and n + 1 be positive consecutive integers such that (n – 1) ×n × (n + 1) = 16 × [(n – 1) + n + (n + 1)]. Simplifying and solving for n, we have n(n2 – 1) = 16 × 3n → n3 – n = 48n → n3 – 49n = 0

    => n(n2 – 49) = 0. So, n = 0 or n2 − 49 = 0 → (n + 7)(n – 7) = 0 => n = −7 or n = 7. Since n is a positive integer, it follows that the three consecutive numbers are 6, 7 and 8. The difference between their product and sum is 6 × 7 × 8 – (6 + 7 + 8) = 336 – 21 = 315. 

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    The ratio of the surface area of Wilbur’s plane to the surface area of Orville’s plane is the square of the scale factor of Wilbur’s mini replica of Orville’s plane. Since Wilbur’s mini replica has linear dimensions that are \(\dfrac{1}{2}\) the size of Orville’s model airplane, it follows that the ratio between the lift forces on Wilbur’s and Orville’s planes is \(\dfrac{1}{2}\times\dfrac{1}{2}=\dfrac{1}{4}\) 

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    If we add the wins of both Flying Turtles and Dolphins, we have to then subtract the 19 wins for the games they played against each other  regardless of who won those games. The value of F + D, then, is 95 + 84 – 19 = 160. 

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    Let x, y be the length and breadth of a rectangle and 16 is the length of diagonal as shown below:

    Using the Pythagorean Theorem in the right triangle formed by sides with the diagonal, we get: x2 + y2 = 2562

    => \(y=\sqrt{256-x^2}\) and \(A\left(x\right)=x\sqrt{256-x^2}\)

    that is the function we have to maximize. Notice that x can vary between x = 0 (the rectangle collapses to a vertical line) and x = 16 (the rectangle collapses to a horizontal line), and in both extremes the area is 0. Let’s find critical points for A:

    \(0=A'\left(x\right)=\sqrt{256-x^2}-x-\dfrac{x}{\sqrt{256-x^2}}\\ \Rightarrow\dfrac{x^2}{\sqrt{256-x^2}}=\sqrt{16-x^2}\\ \Rightarrow x^2=256-x^2\)

    and so \(x=\sqrt{128}\) is the only critical value

    Moreover, A(\(\sqrt{8}\)) = 8 > 8 so it is the maximum

    x y 16

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    A.BC + D.EF = 0.13 + 0.24 = 0.37

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    After the first spin, the probability that the pointer lands on the same color is: 1 : 3 = 1/3

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    We have: 1100112 = 1 x 25 + 1 x 24 + 1 x 21 + 1 x 20 = 5110 =  6 x 81+ 3 x 80 = 638

    So 1100112 is rewritten as 638 in octal (base 8)

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    It is not wrong. Just because of your OLD phone/computer

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    An amicable (or friend) pair  (m,n)  consists of two integers  m,n  for which the sum of proper divisors (the divisors excluding the number itself) of one number equals the other. Amicable pairs are occasionally called friendly pairs (Hoffman 1998, p. 45), although this nomenclature is to be discouraged since the numbers more commonly known as friendly pairs are defined by a different, albeit related, criterion. Symbolically, amicable pairs satisfy

    s(m) = n
    (1)
    s(n) = m
    (2)

    where

    s(n)=sigma(n)-n
    (3)

    is the restricted divisor function. Equivalently, an amicable pair  [(m,n)]  satisfies

    sigma(m)=sigma(n)=s(m)+s(n)=m+n
    (4)

    where  sigma(n)  is the divisor function. The smallest amicable pair is (220, 284) which has factorizations

    220 = 11·5·22
    (5)
    284 = 71·22
    (6)

    giving restricted divisor functions

    s(220) = sum{1,2,4,5,10,11,20,22,44,55,110}
    (7)= 284
    (8)
    s(284) = sum{1,2,4,71,142}
    (9)
    = 220.
    (10)

    The quantity

    sigma(m)=sigma(n)=s(m)+s(n),
    (11)

    in this case,  220+284=504 , is called the pair sum. The first few amicable pairs are (220, 284), (1184, 1210), (2620, 2924) (5020, 5564), (6232, 6368), (10744, 10856), (12285, 14595), (17296, 18416), (63020, 76084), ... (OEIS A002025 and A002046). An exhaustive tabulation is maintained by D. Moews.

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    Still some more, but with "x", "/", ...

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    123-45-67+89=100

    1 + 2 + 3 – 4 + 5 + 6 + 78 + 9 = 100
    123 +45 - 67 + 8 - 9 = 100

    123 + 4- 5 + 67 - 89 = 100
     

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    An amicable pair  [(m,n)]  consists of two integers  [m,n]  for which the sum of proper divisors (the divisors excluding the number itself) of one number equals the other. Amicable pairs are occasionally called friendly pairs (Hoffman 1998, p. 45), although this nomenclature is to be discouraged since the numbers more commonly known as friendly pairs are defined by a different, albeit related, criterion. Symbolically, amicable pairs satisfy

    [s(m)] [=] [n]
    (1)
    [s(n)] [=] [m,]
    (2)

    where

    [s(n)=sigma(n)-n]
    (3)

    is the restricted divisor function. Equivalently, an amicable pair  [(m,n)]  satisfies

    [sigma(m)=sigma(n)=s(m)+s(n)=m+n,]
    (4)

    where  [sigma(n)]  is the divisor function. The smallest amicable pair is (220, 284) which has factorizations

    [220] [=] [11·5·2^2]
    (5)
    [284] [=] [71·2^2]
    (6)

    giving restricted divisor functions

    [s(220)] [=] [sum{1,2,4,5,10,11,20,22,44,55,110}]
    (7)
    [=] [284]
    (8)
    [s(284)] [=] [sum{1,2,4,71,142}]
    (9)
    [=] [220.]
    (10)

    The quantity

    [sigma(m)=sigma(n)=s(m)+s(n),]
    (11)

    in this case,  [220+284=504] , is called the pair sum. The first few amicable pairs are (220, 284), (1184, 1210), (2620, 2924) (5020, 5564), (6232, 6368), (10744, 10856), (12285, 14595), (17296, 18416), (63020, 76084), ... (OEIS A002025 and A002046). An exhaustive tabulation is maintained by D. Moews.

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    Why don't you post some?

  • See question detail

    An amicable pair  [(m,n)]  consists of two integers  [m,n]  for which the sum of proper divisors (the divisors excluding the number itself) of one number equals the other. Amicable pairs are occasionally called friendly pairs (Hoffman 1998, p. 45), although this nomenclature is to be discouraged since the numbers more commonly known as friendly pairs are defined by a different, albeit related, criterion. Symbolically, amicable pairs satisfy

    [s(m)] [=] [n]
    (1)
    [s(n)] [=] [m,]
    (2)

    where

    [s(n)=sigma(n)-n]
    (3)

    is the restricted divisor function. Equivalently, an amicable pair  [(m,n)]  satisfies

    [sigma(m)=sigma(n)=s(m)+s(n)=m+n,]
    (4)

    where  [sigma(n)]  is the divisor function. The smallest amicable pair is (220, 284) which has factorizations

    [220] [=] [11·5·2^2]
    (5)
    [284] [=] [71·2^2]
    (6)

    giving restricted divisor functions

    [s(220)] [=] [sum{1,2,4,5,10,11,20,22,44,55,110}]
    (7)
    [=] [284]
    (8)
    [s(284)] [=] [sum{1,2,4,71,142}]
    (9)
    [=] [220.]
    (10)

    The quantity

    [sigma(m)=sigma(n)=s(m)+s(n),]
    (11)

    in this case,  [220+284=504] , is called the pair sum. The first few amicable pairs are (220, 284), (1184, 1210), (2620, 2924) (5020, 5564), (6232, 6368), (10744, 10856), (12285, 14595), (17296, 18416), (63020, 76084), ... (OEIS A002025 and A002046). An exhaustive tabulation is maintained by D. Moews.

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    Your answer is incorrect, try again

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    SORRY, the answer is incorrect, but I have made a mistake when for him

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    You can see the answer at: http://www.math.uconn.edu/~kconrad/blurbs/grouptheory/15puzzle.pdf

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    P/s: You always type incorrectly

    Ex: Standand, not stardard

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    The probablity of rolling one first time is \(\dfrac{1}{6}\)

    Six times that, we have: \(\left(\dfrac{1}{6}\right)^6\)=\(\dfrac{1}{46656}\)

    But is this correct, because it is BEST IQ, right?

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Questions ( 21 )
  • Every week (starting from question 1) I will post 6 - 7 questions to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTION THIS TIME IS:

    19) Given\(\Delta ABC\) (AB = AC), \(\widehat{A}\) = 20o. Take point D on AB that AD = BC

         Find \(\widehat{ACD}\)  A B C D A This picture is for illustration purposes only

    Every solution worths one point

  • Every week (starting from question 1) I will post 6 - 7 questions to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTIONS TODAY ARE:

    17) Prove that: \(G=\dfrac{3}{4}+\dfrac{5}{36}+\dfrac{7}{144}+...+\dfrac{2n+1}{n^2\left(n+1\right)^2}< 1\)

    18) Prove that: \(L=\dfrac{1}{2!}+\dfrac{5}{3!}+\dfrac{11}{4!}+...+\dfrac{n^2+n-1}{\left(n+1\right)!}< 2\)

  • Every week (starting from question 1) I will post 6 - 7 questions to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTIONS TODAY ARE:

    15) A box of chocolate has gone missing from the refrigerator. The suspects have been reduced to 4 children. Only one of them is telling the truth.

         John: "I didn't take the chocolate"

         Wendy: "John is lying"

         Charlies: "Wendy is lying"

         Sally: "Wendy took the chocolate"

    Who took the chocolate?

    16) Given:

         8 + 1 + 3 = 3

         9 + 0 + 9 = 9

         4 + 5 + 3 = 3

        1 + 4 + 6 + 2 = ?

    Find the missing number

     

     

  • Everyday (starting from question 1) I will post 1 - 2 question(s) to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTION TODAY IS:

    14) A rectangle is folded like below. Knowing that the area of figure 2 is \(\dfrac{2}{3}\) the rectangle and the area of the slashed triangle is 24 cm2. Find the area of the rectangle

      Figure 1 Figure 2  

  • Everyday (starting from question 1) I will post 1 - 2 question(s) to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTIONS TODAY ARE:

    12) Given \(\Delta ABC\) (AB = AC). Find\(\widehat{ABC}\) 


    B L K A C

    13) Andy and Beth is in a race at the pool. Andy runs around the pool while Beth swims by the length of the pool. Knowing that:

         - Andy is three times as fast as Beth

         - The time Beth swims 5 turns is equal to the time that Andy runs 6 turns around the pool

         - The length of the pool is 50m

    What is the width of the pool?

  • Everyday (starting from question 1) I will post 1 - 2 question(s) to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTION TODAY IS:

    11) Mr. Cook bought a big box of his favourite Halloween candies to hand out to trick-or-treaters. However,
    he ate half of all the candies himself before the first child came and took her share. He ate half of what
    was left before the second child came, and half of what was left again before the third child came and
    took all of the remaining candies. If it is known that each child received the same number of candies,
    which of the following statements is certainly true about how many candies Mr. Cook originally bought?
    (A) It is a multiple of 3

    (B) It is a multiple of 4

    (C) It is a multiple of 6

    (D) It is a multiple of 7

    (E) It is a multiple of 11

    (Full answer please)

  • Everyday (starting from question 1) I will post 1 - 2 question(s) to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTION TODAY IS:

    10) Given \(\Delta ABC\) (\(\widehat{A}=90^o\), AB = AC). O is the intersection point of 3 perpendicular bisectors; I is the intersection point of 3 bisectors in the triangle

        a/ Given AB = c, BC = a, CA = b, \(p=\dfrac{a+b+c}{2}\), r is the distance from I to BC

          Prove that r = p - a

        b/ Prove that if \(\Delta ABC\) rights, it must right at I

    (Draw the figure if possible)

  • Everyday (starting from question 1) I will post 1 - 2 question(s) to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTION TODAY IS:

    9) Find 3 positive integers x, y, z that satisfy:

       - \(x^3-y^3-z^3=3xyz\)

       - The area of  the square that includes side x = The perimeter of the rectangle with sides y, z

     

     
  • Everyday (starting from question 1) I will post 1 - 2 question(s) to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTIONS TODAY ARE:

    7)  Given 3 integers a, b and c that satisfy: a2 = b2 + c2. Prove that a.b.c\(⋮\) 60

    8) Find the smallest value of \(\overline{abcd}\) that satisfy: \(\overline{abcd}=7\times\overline{ab}\times\overline{ad}\)

    Remember: - You just need to answer 1 of these

                        - One point/answer/question 

     

  • Everyday (starting from question 1) I will post 1 - 2 question(s) to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTION TODAY IS:

    6) Find x that satisfy:

    - \(x\in Q\), x2 is a square number

    - x2 + 5 and x2 - 5 are also square number

    Let's see who can solve this

    Your IQ will be over 150 if you can

  • Everyday (starting from question 1) I will post 1 - 2 question(s) to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTION TODAY IS:

    5) Given as shown:

    • square ABCD
    • equilateral triangle ABE and BDF

    Find  \(\angle EFD\:\)

    (MYTS - 2018 - Grade 7)

      A B C D E F

  • Everyday (starting from question 1) I will post 1 - 2 question(s) to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTION TODAY IS:

    4) Find the smallest positive integers N such that:

    - \(N⋮99\)

    - N doesn't include digit 9

    ( MYTS - 2018 - Grade 7)

  • Everyday (starting from question 1) I will post 1 - 2 question(s) to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTION TODAY IS:

    3) Find the smallest prime number including 3 digits \(\overline{abc}\) that \(a,\overline{ab},\overline{abc},c,\overline{cb},\overline{cba}\) are also prime numbers

    (MYTS - 2018 - Grade 7)

  • Everyday (starting from question 1) I will post 1 - 2 question(s) to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTION TODAY IS:

    2) Given \(\Delta ABC\)  right at A

        AB = 3 cm & AC = 4 cm

        Draw a square BCED outside the triangle A B C D E 4 3

        What is the length of AD?

    (MYTS - 2018 - Grade 7)

  • Everyday (starting from question 1) I will post 1 - 2 question(s) to get a point:

    - The fastest person who answer correctly will get 1 point/question/answer

    - You can still answer my old question at https://mathulike.com/discuss/member/leanhduy0206 and get point

    THE QUESTION TODAY IS:

    1) The odd numbers is sorted into rows below:

    1

    3     5

    7     9     11

    13     15     17    19    

    21     23     25     27     29

    ...       ...      ...      ...      ...     ...     ...

    What is the sum of the numbers in row 20?

    (MYTS - 2018 - Grade 7)

     

     

  • Given \(A=2018^2-2017^2+2016^2-2015^2+...+2^2-1^2\)

    Find the last two digits of A

  • How many prime numbers maximumly are there in 100 consecutive natural numbers?

  • Find the last two digits of \(7^{107}\)

  • In this figure, \(\angle GJA=113^o\)

    \(\angle A+\angle B+\angle C+\angle D+\angle E+\angle F+\angle G=x^o\)

    Find x A B C D E F G J J 113 This picture is for illustration purposes only

  • A natural number N is called gallant number if N is divisible by its digits and the sum of its digits

        Ex: 12 is a gallant number because \(12⋮1;2;1+2\)

              102 is not a gallant number because \(102⋮1;2;1+0+2\) but \(102⋮̸0\)

    Find the smallest gallant number that is divisible by 11

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