So as to have the function be increasing, 2016-m² must be positive. Therefore, 2016 must be greater than m². Since 2016 is a positive number, m has to range from \(-\sqrt{2016}\) to \(\sqrt{2016}\). In other words, m has to be between -44.899 and 44.899. Since m is a whole number, the minimal value of m is -44 and the maximum is 44. To calculate the number of values, we use this formula:
\(N=\frac{44-(-44)}{1}+1=89\)

To conclude, there are 89 values of m such that the function is increasing.

The sum of the three numbers is 120.
The sum of the two remaining numbers is 101.
The lowest possible value for the second number is 20.
So the highest number would be 81.

Analyzing the numbers first, we can see that each number increases by 1, 2, 3, 4, 5 ... progressively arithmetically increasing.
So the number that comes next is definitely 22
Analyzing the letters, it will be the order of the letter in the Latin alphabet.
So the letter is V
So it's V22

Mininum divisors? That is the number 1, obviously

Or did you mean the minimum NUMBER of divisors?
If so than it's 9, how you ask?
To create less permutations with the divisors, the factors should overlap the most, hence, the 6 divisor number is a⁵ and the 4 divisor number is a³, so the product would be a⁸, having 9 divisors.

M=2
A=1
T=7
H=8
MATH=2178
How did I solve this? Continuous trial and error.

\(x+4567108=\left(-4566109\right)\)
\(x=\left(-4566109\right)-4567108=-9133217\)
\(x\times\left(-8\right)=\left(-9133217\right)\times\left(-8\right)=73065736\)
I have no idea how one is supposed to do this without a calculator

We have the domain of f(x), time to replace all of these values into the variables...
After a while of repetition, we will get the range of f(x) is {-3;-2;1;6;13}
So the intersection of these two sets is {-3;-2;1}

*written that

7 numbers: 0,1,2,3,4,5,6 written that in both bases

b=2772 and a=757

I don't think this needs much explanation, G is obviously 1.
L=5 and S=8, hence M=9

I'm not sure, probably 2 because...
2=1+1
5=4+1
8=7+1
11=10+1
14=13+1
17... IDK
I'm not sure, probably 2

So I've said, it's 2x²-x+7

Simplifying? Okay
\(\dfrac{2}{x-1}+\dfrac{2x-1}{x^2+x+1}-\dfrac{x^2+6x+2}{1-x}=\dfrac{2}{x-1}+\dfrac{2x-1}{x^2+x+1}+\dfrac{x^2+6x+2}{x-1}\)

Condition for x: \(x\ne1\)
\(\dfrac{2\left(x^2+x+1\right)}{x^3-1}+\dfrac{\left(2x-1\right)\left(x-1\right)}{x^3-1}+\dfrac{\left(x^2+6x+2\right)\left(x-1\right)}{x^3-1}\)
\(\Rightarrow2x^2+2x+2+2x^2-2x-x+1+x^3+6x^2+2x-x^2-6x-2\)
\(=x^3+3x^2-5x+1\)
(I can't factorize that polynomial )

a. \(11^2=121;20^2=400\) so the answer is 400
b. \(3^3=27;4^3=64\) so the answer is 64

1) The smallest 3 digit prime number is 101. The biggest 4 digit prime number is 9973. And the sum of those numbers is 10074.
2) Anna walked \(8762-80^2=8762-6400=2362\left(m\right)\) more than Becky. (Those mad girls walking such long distances for no reason)
3) The biggest number among them is C)8977

\(v_{tb}=\dfrac{s+s}{t_1+t_2}=\dfrac{2s}{\dfrac{s}{v_1}+\dfrac{s}{v_2}}=\dfrac{2}{\dfrac{v_1+v_2}{v_1v_2}}=\dfrac{2v_1v_2}{v_1+v_2}=\dfrac{2\cdot4\cdot12}{4+12}=\dfrac{96}{16}=6\left(mph\right)\)

After each round, the number of people will divide by half.
So 32 => 16 => 8 => 4 => 2 => Champion
The number of matches each round will be determined by the value of HALF the number of participants:
So there will be 16+8+4+2+1=31(matches)

The 500th number will be 5+6(500-1)=2999

The sum of each numbers of each set is 15
So the last digit in set g is 4