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Answers ( 25 )
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    \(10+20+30+40+50+60+70+80+90\)

    \(=\left(10+90\right)+\left(20+80\right)+\left(30+70\right)+\left(40+60\right)+50\)

    \(=100+100+100+100+50\)

    \(=400+50\)

    \(=450\)

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    The average of 6, 8 and 16 is:

    \(\dfrac{6+8+16}{3}=\dfrac{30}{3}=10\)

    Answer: 10

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    We have: \(\dfrac{10+10+10}{3}=\dfrac{30}{3}=10\)

    So the average of 10 + 10 + 10 is 10.

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    \(M=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)\)

    \(M=\dfrac{5}{7}.\dfrac{-7}{11}\)

    \(M=\dfrac{-5}{11}\)

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    Welcome!

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    \(3^2+3^3+3^4=9+27+81=117\)

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    Don't you ask and answer by yourself?

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    You left: 130 - 100 = 30 (apples)

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    20 + 80 + 40 + 50 + 20 + 60

    = (20 + 80) + (40 + 60) + 50 + 20

    = 100 + 100 + 50 + 20

    = 270

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    The age of the younger sister in this year is: (43 - 7) : 2 = 18 (years old)

    The age of the younger sister in 7 years later is: 18 + 7 = 25 (years old)

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    We have:

    \(4=2^2\)

    \(8=2^3\)

    \(10=2.5\)

    \(\Rightarrow LCM\left(4;8;10\right)=2^3.5=40\)

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    What do you mean? I just rewrite the question! The one who asked is Lula Nguyễn, not me!

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    \(A=\dfrac{2}{4.5}+\dfrac{2}{5.6}+\dfrac{2}{6.7}+...+\dfrac{2}{15.16}\)

    \(A=2\left(\dfrac{1}{4.5}+\dfrac{1}{5.6}+\dfrac{1}{6.7}+...+\dfrac{1}{15.16}\right)\)

    \(A=2\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{15}-\dfrac{1}{16}\right)\)

    \(A=2\left(\dfrac{1}{4}-\dfrac{1}{16}\right)\)

    \(A=2.\dfrac{3}{16}\)

    \(A=\dfrac{6}{16}=\dfrac{3}{8}\)

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    \(A=\dfrac{\left(1+50\right).50}{2}\)

    \(A=\dfrac{51.50}{2}\)

    \(A=\dfrac{2550}{2}\)

    \(A=1275\)

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    Faded and Fake! This topic isn't a question, you shouldn't post it anymore.

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    \(A=2^2.2^3.2^4.2^5\)

    \(A=2^{2+3+4+5}\)

    \(A=2^{14}\)

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    a) 46 + 17 + 54

    = (46 + 54) + 17

    = 100 + 17

    = 117

    b) 4 . 35 . 25

    = (4 . 25) . 35

    = 100 . 35

    = 3500

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    \(x-10+2=20+10\)

    \(\Leftrightarrow x-8=30\)

    \(\Leftrightarrow x=30+8\)

    \(\Leftrightarrow x=38\)

    Check my answer, it's shorter than the others people's answer.

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    We have:

    \(10=2.5\)

    \(20=2^2.5\)

    \(30=2.3.5\)

    \(\Rightarrow GCD\left(10;20;30\right)=2.5=10\)

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    We have:SCM

    \(4=2^2\)

    \(6=2.3\)

    \(8=2^3\)

    \(\Rightarrow SCM\left(4;6;8\right)=2^3.3=24\)

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