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\(10+20+30+40+50+60+70+80+90\)
\(=\left(10+90\right)+\left(20+80\right)+\left(30+70\right)+\left(40+60\right)+50\)
\(=100+100+100+100+50\)
\(=400+50\)
\(=450\)
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The average of 6, 8 and 16 is:
\(\dfrac{6+8+16}{3}=\dfrac{30}{3}=10\)
Answer: 10
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We have: \(\dfrac{10+10+10}{3}=\dfrac{30}{3}=10\)
So the average of 10 + 10 + 10 is 10.
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\(M=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)\)
\(M=\dfrac{5}{7}.\dfrac{-7}{11}\)
\(M=\dfrac{-5}{11}\)
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Welcome!
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\(3^2+3^3+3^4=9+27+81=117\)
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Don't you ask and answer by yourself?
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You left: 130 - 100 = 30 (apples)
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20 + 80 + 40 + 50 + 20 + 60
= (20 + 80) + (40 + 60) + 50 + 20
= 100 + 100 + 50 + 20
= 270
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The age of the younger sister in this year is: (43 - 7) : 2 = 18 (years old)
The age of the younger sister in 7 years later is: 18 + 7 = 25 (years old)
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We have:
\(4=2^2\)
\(8=2^3\)
\(10=2.5\)
\(\Rightarrow LCM\left(4;8;10\right)=2^3.5=40\)
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What do you mean? I just rewrite the question! The one who asked is Lula Nguyễn, not me!
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\(A=\dfrac{2}{4.5}+\dfrac{2}{5.6}+\dfrac{2}{6.7}+...+\dfrac{2}{15.16}\)
\(A=2\left(\dfrac{1}{4.5}+\dfrac{1}{5.6}+\dfrac{1}{6.7}+...+\dfrac{1}{15.16}\right)\)
\(A=2\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{15}-\dfrac{1}{16}\right)\)
\(A=2\left(\dfrac{1}{4}-\dfrac{1}{16}\right)\)
\(A=2.\dfrac{3}{16}\)
\(A=\dfrac{6}{16}=\dfrac{3}{8}\)
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\(A=\dfrac{\left(1+50\right).50}{2}\)
\(A=\dfrac{51.50}{2}\)
\(A=\dfrac{2550}{2}\)
\(A=1275\)
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Faded and Fake! This topic isn't a question, you shouldn't post it anymore.
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\(A=2^2.2^3.2^4.2^5\)
\(A=2^{2+3+4+5}\)
\(A=2^{14}\)
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a) 46 + 17 + 54
= (46 + 54) + 17
= 100 + 17
= 117
b) 4 . 35 . 25
= (4 . 25) . 35
= 100 . 35
= 3500
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\(x-10+2=20+10\)
\(\Leftrightarrow x-8=30\)
\(\Leftrightarrow x=30+8\)
\(\Leftrightarrow x=38\)
Check my answer, it's shorter than the others people's answer.
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We have:
\(10=2.5\)
\(20=2^2.5\)
\(30=2.3.5\)
\(\Rightarrow GCD\left(10;20;30\right)=2.5=10\)
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We have:SCM
\(4=2^2\)
\(6=2.3\)
\(8=2^3\)
\(\Rightarrow SCM\left(4;6;8\right)=2^3.3=24\)
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