A = \(\dfrac{1}{1.2}\) +  \(\dfrac{1}{2.3}\) + \(\dfrac{1}{3.4}\) + ... + \(\dfrac{1}{99.100}\)

A = 1 - \(\dfrac{1}{2}\) +  \(\dfrac{1}{2}\) - \(\dfrac{1}{3}\) +  \(\dfrac{1}{3}\) - \(\dfrac{1}{4}\) + ... + \(\dfrac{1}{99}\) - \(\dfrac{1}{100}\)

A = 1 -\(\dfrac{1}{100}\)

A = \(\dfrac{99}{100}\)

Đáp án là c

đáp án là c

tk nha

3 kg

3 kg

tk nhé

Nick will need : \(1\dfrac{3}{4}\) +  \(3\dfrac{3}{4}\) = \(\dfrac{11}{2}\) = \(5,5\)

a = \(\dfrac{2}{3}\)

2/3 nhé

tk nhé