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a-b=-4
\(\Rightarrow\)2a-2b=-8
\(\Rightarrow\)a+2b+2a-2b=11-8
\(\Rightarrow\)3a=3
\(\Rightarrow\)a=1
\(\Rightarrow\)b=a+4=1+4=5
\(\Rightarrow\)4a-b=1.4-5=4-5=-1
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a) 3x (12x - 4) - 9x (4x - 3) = 30
\(\Leftrightarrow\)36x2 – 12x – 36x2 + 27x = 30
\(\Leftrightarrow\)15x = 30
\(\Leftrightarrow\)x = 2
b) x (5 - 2x) + 2x (x - 1) = 15
\(\Leftrightarrow\)5x – 2x2 + 2x2 – 2x = 15
\(\Leftrightarrow\)3x = 15
\(\Leftrightarrow\)x =5
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1+2+3+4+5+6+7+8
=(2+8)+(3+7)+(4+6)+1+5
=10+10+10+6
=10.3+6
=30+6
=36
So the answer is 36
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1+2+3+4+5+6+7+8
=(2+8)+(3+7)+(4+6)+1+5
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\(\dfrac{3}{m}=\dfrac{27}{72}\\\Leftrightarrow \dfrac{3.9}{9m}=\dfrac{27}{72}\\\Leftrightarrow \dfrac{27}{9m}=\dfrac{27}{72}\\ \Rightarrow9m=72\\ \Rightarrow m=8\)
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23 rows of 27 chairs each
So 23.27=621 (chairs)
So there are 621 chairs in the room
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The absolute difference between the length and width of rectangle MNOP is |(4x+9)-(4x-3)|
=|4x+9-4x+3|
=|12|
=12
So the answer is 12
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2011x=x2011
So 20112011=xx
So x=2011
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2x+2y+2z=1024
but 1024=512+256+256
so \(\left[{}\begin{matrix}\left\{{}\begin{matrix}x=9\\y=8\\z=8\end{matrix}\right.\\\left\{{}\begin{matrix}x=8\\y=9\\z=8\end{matrix}\right.\\\left\{{}\begin{matrix}x=8\\y=8\\z=9\end{matrix}\right.\end{matrix}\right.\)
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x2+x+1\(\ne\)0 with any value of x
So don't have any value of x satisfy
So don't have any value of A
So A\(\in\)\(\varnothing\)
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1+2+3+10000000
=(1+2+3)+10000000
=6+10000000
=10000006
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10+20+30+40+50+60+70+80+90
=(10+90)+(20+80)+(30+70)+(40+60)+50
=100+100+100+100+50
=100.4+50
=400+50
=450
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x:3:2=9
\(\Leftrightarrow x=9.2.3\)
\(\Leftrightarrow x=54\)
So the answer is 54
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S dodecagon = S original rectangle - S removed squares
S original rectangle = 4.5=20 (cm2)
S removed squares = 12.4=4 (cm2)
So S dodecagon = 20-4=16 (cm2)
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20+30+40+50+60+70
=(20+30+50)+(40+60)+70
=100+100+70
=100.2+70
=200+70
=270
So the answer is 270
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=(1+9)+(2+8)+(3+7)+(4+6)+10+5
=10+10+10+10+10+5
=10.5+5
=50+5
=55
So the answer is 55
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99999.55555
=(100000-1).55555
=5555500000-55555
=5555444445
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40%\(\times\dfrac{1}{3}\times24\div0,8\)
=\(\dfrac{40.1.24}{100.3}\div\dfrac{4}{5}\)
=\(\dfrac{16}{5}.\dfrac{5}{4}\)
= 4
So the answer is 4
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we have : 0,0A=\(\sqrt{0,0049}\)
but \(\sqrt{0,0049}=0,07\)
\(\Rightarrow0,0A=0,07\)
\(\Rightarrow A=7\)
So the value of A is 7
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a,x=100-33=67
b,x=100-88=12
c,x=100-22=78
d,x=100-18=82
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