A = 1 +\(\dfrac{1}{2}\)(1 + 2) +\(\dfrac{1}{3}\)(1 + 2 + 3) + ... +\(\dfrac{1}{2017}\)(1 + 2 + 3 + ... + 2017)

B = (2\(\dfrac{5}{6}\)+\(\dfrac{4}{9}\)): (10\(\dfrac{1}{12}\)-9\(\dfrac{1}{2}\))

C = 1\(\dfrac{5}{18}\):\(\dfrac{5}{18}\)(\(\dfrac{1}{15}\)+1\(\dfrac{1}{12}\))

D = -\(\dfrac{1}{7}\)(9\(\dfrac{1}{2}\)-8,75):\(\dfrac{2}{7}\)+0.625: 1\(\dfrac{2}{3}\)