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We have:
⇒a=2017n−2016b⇒a=2017n−2016b
We have: 2a+2015b=2(2017n−2016b)+2015b=2.2017n−2017b⋮2017
We have:
⇒a=2017n−2016b⇒a=2017n−2016b
We have: 2a+2015b=2(2017n−2016b)+2015b=2.2017n−2017b⋮20172a+2015b=2(2017n−2016b)+2015b=2.2017n−2017b⋮2017
Same as above. We hava: ⎧⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎨⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎩3a+2014b=3.2017n−2.2017b⋮20174a+2013b=4.2017n−3.2017b⋮2017...2015a+2b=2015.2017n−2014.2017b{3a+2014b=3.2017n−2.2017b⋮20174a+2013b=4.2017n−3.2017b⋮2017...2015a+2b=2015.2017n−2014.2017b
So that: A⋮2017.2017...2017A⋮2017.2017...2017
⇒A⋮20172014
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We have : 100 + 500 : 5 - 40
= 100 + 100 - 40
= 200 - 40
= 160
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If p = 2 then p + 8 isn't a prime number.
If p = 3 then p + 8 and p + 16 are prime numbers.
⇒32+(3+8)2+(3+16)2=491⇒32+(3+8)2+(3+16)2=491
If p > 3 then [p=3k+1p=3k+2[p=3k+1p=3k+2
+ If p = 3k + 1 then p + 8 = 3k + 9=3(k+1) isn't a prime number.
+ If p = 3k + 2 then p + 16 = 3k + 18=3(k+6) isn't a prime number.
Ans: 491.
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Run my EDM 15 hour before (21:01)
a + b + c = 72, then there's an even number and two odd numbers.
The only even prime number is 2, so a = 2.
b+c=70=3+67=7+61=11+59=17+53=23+47=29+41Ans : a = 2 and (b;c)∈{(3;67);(67;3);(7;61);(61;7);(11;59);(59;11);(17;53);(53;17);(23;47);(47;23);(29;41);(41;29)}
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Nguyễn Việt Hoàng 18 hour before (17:56)
From 7m + 5n = 31, we can see that 7m or 5n is even.
- If 7m is even, m is even and prime => m = 2.
=> 5n = 31 - 7 x 2 = 17. n ⋮̸⋮̸ 5, so no numbers sastify the problem.
- If 5n is even, n is even and prime => n = 2.
=> 7m = 31 - 5 x 2 = 21 => m = 3 is a prime number.
The value of: mn + nm = 32 + 23 = 9 + 8 = 17.
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We have:
⇒a=2017n−2016b
We have: 2a+2015b=2(2017n−2016b)+2015b=2.2017n−2017b⋮2017
Same as above. We hava: ⎧⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎨⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎩3a+2014b=3.2017n−2.2017b⋮20174a+2013b=4.2017n−3.2017b⋮2017...2015a+2b=2015.2017n−2014.2017b
So that: A⋮2017.2017...2017
⇒A⋮20172014
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We have : A = 1.2 + 2.3 + 3.4 + ...... + 100.101
=> 3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ....... + 99.100.101
=> 3A = 99.100.101
=> A = 99.100.101/3
=> A = 333300
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B = 1 + 2 + 3 + ...... + 100
B is numbered as:
100 - 1 + 1 = 100 (số)
Total B is:
(100 x 101) : 2 = 5050
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Put A = 1.3 + 3.5 + 5.7 + ...... + 99.101
=> 4A = 1.3.(5 - 1) + 3.5.(7 - 3) + ...... + 99.101.(103 - 99)
=> 4A = 1.3.5 - 1.3.5 + 3.5.7 - 3.5.7 + ...... + 99.100.101
=> 4A = 99.100.101
=> A = 99.100.101/4
=> A = 249975
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Put A = 1.3 + 3.5 + 5.7 + ...... + 99.101
=> 4A = 1.3.(5 - 1) + 3.5.(7 - 3) + ...... + 99.101.(103 - 99)
=> 4A = 1.3.5 - 1.3.5 + 3.5.7 - 3.5.7 + ...... + 99.100.101
=> 4A = 99.100.101
=> A = 99.100.101/4
=> A = 249975
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Put : A = 1.3 + 3.5 + 5.7 + ...... + 99.101
=> 4A = 1.3.(5 - 1) + 3.5.(7 - 3) + ...... + 99.101.(103 - 99)
=> 4A = 1.3.5 - 1.3.5 + 3.5.7 - 3.5.7 + ...... + 99.100.101
=> 4A = 99.100.101
=> A = 99.100.101/4
=> A = 249975
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Put A = 1.2 + 2.3 + 3.4 + ....... + 199.200
=> 3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ....... + 199.200.201
=> 3A = 199.200.201
=> A = 199.200.201/3
=> A = 2666600
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Put A = 1.2 + 2.3 + 3.4 + ....... + 199.200
=> 3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ....... + 199.200.201
=> 3A = 199.200.201
=> A = 199.200.201/3
=> A = 2666600
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Put A = 1.2 + 2.3 + 3.4 + ....... + 199.200
=> 3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ....... + 199.200.201
=> 3A = 199.200.201
=> A = 199.200.201/3
=> A = 2666600
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That worker makes 3 tools out of time is:
12 hours - 7 hours 30 minute = 4 hours 30 minute = 4,5 hours
The worker makes 1 product time out is :
4,5 : 3 = 1,5 (hours)
Answer : 1,5 hours
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That worker makes 3 tools out of time is:
12 hours - 7 hours 30 minute = 4 hours 30 minute = 4,5 hours
The worker makes 1 product time out is :
4,5 : 3 = 1,5 (hours)
Answer : 1,5 hours