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Answers ( 38 )
  • See question detail

    We have: 

    ⇒a=2017n−2016b⇒a=2017n−2016b

    We have: 2a+2015b=2(2017n−2016b)+2015b=2.2017n−2017b⋮2017

    We have: 

    ⇒a=2017n−2016b⇒a=2017n−2016b

    We have: 2a+2015b=2(2017n−2016b)+2015b=2.2017n−2017b⋮20172a+2015b=2(2017n−2016b)+2015b=2.2017n−2017b⋮2017

    Same as above. We hava: ⎧⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎨⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎩3a+2014b=3.2017n−2.2017b⋮20174a+2013b=4.2017n−3.2017b⋮2017...2015a+2b=2015.2017n−2014.2017b{3a+2014b=3.2017n−2.2017b⋮20174a+2013b=4.2017n−3.2017b⋮2017...2015a+2b=2015.2017n−2014.2017b

    So that: A⋮2017.2017...2017A⋮2017.2017...2017

    ⇒A⋮20172014

  • See question detail

    We have : 100 + 500 : 5 - 40 

    = 100 + 100 - 40

    = 200 - 40

    = 160 

  • See question detail

    If p = 2 then p + 8 isn't a prime number.

    If p = 3 then p + 8 and p + 16 are prime numbers.

      ⇒32+(3+8)2+(3+16)2=491⇒32+(3+8)2+(3+16)2=491

    If p > 3 then [p=3k+1p=3k+2[p=3k+1p=3k+2

      + If p = 3k + 1 then p + 8 = 3k + 9=3(k+1) isn't a prime number.

      + If p = 3k + 2 then p + 16 = 3k + 18=3(k+6) isn't a prime number.

    Ans: 491.

  • See question detail
    Run my EDM 15 hour before (21:01)

    a + b + c = 72, then there's an even number and two odd numbers.

    The only even prime number is 2, so a = 2.

    b+c=70=3+67=7+61=11+59=17+53=23+47=29+41b+c=70=3+67=7+61=11+59=17+53=23+47=29+41Ans : a = 2 and (b;c)∈{(3;67);(67;3);(7;61);(61;7);(11;59);(59;11);(17;53);(53;17);(23;47);(47;23);(29;41);(41;29)}

  • See question detail
    Nguyễn Việt Hoàng 18 hour before (17:56)

    From 7m + 5n = 31, we can see that 7m or 5n is even.

    - If 7m is even, m is even and prime => m = 2.

    => 5n = 31 - 7 x 2 = 17. n ⋮̸⋮̸ 5, so no numbers sastify the problem.

    - If 5n is even, n is even and prime => n = 2.

    => 7m = 31 - 5 x 2 = 21 => m = 3 is a prime number.

    The value of: mn + nm = 32 + 23 = 9 + 8 = 17.

  • See question detail

    We have: 

    ⇒a=2017n−2016b⇒a=2017n−2016b

    We have: 2a+2015b=2(2017n−2016b)+2015b=2.2017n−2017b⋮2017

    Same as above. We hava: ⎧⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎨⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎩3a+2014b=3.2017n−2.2017b⋮20174a+2013b=4.2017n−3.2017b⋮2017...2015a+2b=2015.2017n−2014.2017b

    So that: A⋮2017.2017...2017A⋮2017.2017...2017

    ⇒A⋮20172014

  • See question detail

    We have : A = 1.2 + 2.3 + 3.4 + ...... + 100.101

        =>       3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ....... + 99.100.101 

        =>       3A = 99.100.101

        =>         A = 99.100.101/3

        =>         A = 333300

  • See question detail

    B = 1 + 2 + 3 + ...... + 100

    B is numbered as:

               100 - 1 + 1 = 100 (số)

    Total B is:

               (100 x 101) : 2 = 5050 

                      

  • See question detail

    Put A = 1.3 + 3.5 + 5.7 + ...... + 99.101

    => 4A = 1.3.(5 - 1) + 3.5.(7 - 3) + ...... + 99.101.(103 - 99)

    => 4A = 1.3.5 - 1.3.5 + 3.5.7 - 3.5.7 + ...... + 99.100.101

    => 4A = 99.100.101

    => A = 99.100.101/4

    => A = 249975

  • See question detail

    Put A = 1.3 + 3.5 + 5.7 + ...... + 99.101

    => 4A = 1.3.(5 - 1) + 3.5.(7 - 3) + ...... + 99.101.(103 - 99)

    => 4A = 1.3.5 - 1.3.5 + 3.5.7 - 3.5.7 + ...... + 99.100.101

    => 4A = 99.100.101

    => A = 99.100.101/4

    => A = 249975

  • See question detail

    Put : A = 1.3 + 3.5 + 5.7 + ...... + 99.101

    => 4A = 1.3.(5 - 1) + 3.5.(7 - 3) + ...... + 99.101.(103 - 99)

    => 4A = 1.3.5 - 1.3.5 + 3.5.7 - 3.5.7 + ...... + 99.100.101

    => 4A = 99.100.101

    => A = 99.100.101/4

    => A = 249975

  • See question detail

    Put A = 1.2 + 2.3 + 3.4 + ....... + 199.200

     => 3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ....... + 199.200.201

    => 3A = 199.200.201

    => A = 199.200.201/3

    => A = 2666600

  • See question detail

    Put A = 1.2 + 2.3 + 3.4 + ....... + 199.200

     => 3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ....... + 199.200.201

    => 3A = 199.200.201

    => A = 199.200.201/3

    => A = 2666600

  • See question detail

    Put A = 1.2 + 2.3 + 3.4 + ....... + 199.200

     => 3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ....... + 199.200.201

    => 3A = 199.200.201

    => A = 199.200.201/3

    => A = 2666600

  • See question detail

    That worker makes 3 tools out of time is:

                              12 hours - 7 hours 30 minute = 4 hours 30 minute = 4,5 hours

    The worker makes 1 product time out is :  

                              4,5 : 3 = 1,5 (hours)

                                     Answer : 1,5 hours

  • See question detail

    That worker makes 3 tools out of time is:

                              12 hours - 7 hours 30 minute = 4 hours 30 minute = 4,5 hours

    The worker makes 1 product time out is :  

                              4,5 : 3 = 1,5 (hours)

                                     Answer : 1,5 hours

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