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1st way :10 + 20 + 60 + 40 + 80 + 90
=(1 + 2 + 6 + 4 + 8 + 9) x 10
=30 x 10
=300
2nd way :10 + 20 + 60 + 40 + 80 + 90
=(10 + 90) + (20 + 80) + (60 + 40)
=100 + 100 + 100
=100 x 3
=300
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We have:
x=60 : \(\dfrac{1}{3}\)=180
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We have :
6.(a + 5)=90
<=>a + 5=15
=>a=10
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* is 8
=>738 :2 and 9
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The circumference of circle is:
2 x 2 x 3,14`=12,56(cm)
Answer:12,56 cm
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10 + 35 + 100 : 25 25 + 15 + 10 + 80 : 4
=10 + 35 + 4 =25 + 15 + 10 + 20
=45 + 4 =40 + 30
=49 =70
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The average of 5, 10, 30 is:
\(\dfrac{5+10+30}{3}\)=\(\dfrac{45}{3}\)=15
Answer:15
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The average of 20, 10, 60 is:
\(\dfrac{20+10+60}{3}\)=\(\dfrac{90}{3}\)=30
Answer:30
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The average of 23, 67, 108 is:
\(\dfrac{23+67+108}{3}\)=\(\dfrac{198}{3}\)=66
Answer:66
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\(\sqrt{3375}\)=\(15\sqrt{15}\)
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x - \(\dfrac{7}{5}\)=\(\dfrac{3}{7}\)
x=\(\dfrac{3}{7}\) + \(\dfrac{7}{5}\)
x=\(\dfrac{64}{35}\)
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1st way :10+ 20 + 30 + 40 + 50 + 60 + 70 + 80
=(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8) .10
=36 . 10
=360
2ndway:10 + 20 + 30 + 40 + 50 + 60 + 70 + 80
=(20 + 80) + (30 + 70) + (40 + 60) + (10 + 50)
=100 + 100 + 100 + 50
=300 + 60
=360
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1st way :10+ 20 + 30 + 40 + 50 + 60 + 70 + 80
=(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8) .10
=36 . 10
=360
2ndway:10 + 20 + 30 + 40 + 50 + 60 + 70 + 80
=(20 + 80) + (30 + 70) + (40 + 60) + (10 + 50)
=100 + 100 + 100 + 50
=300 + 50
=350
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100 + 200 + 300 + 500 + 700 + 800 + 900 200 + 300 + 400 + 100 + 700 + 600 + 900
=(100 + 900) + (200 + 800) + (300 + 700) + 500 =(300 + 700) + (400 + 600) + (100 + 900) + 200
=1000 + 1000 + 1000 + 500 =1000 + 1000 + 1000 + 200
=3000 + 500 =3000 + 200
=3500 =3200
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10 + 20 + 30 + 40 + 50 + 60 + 70 + 80 + 90 + 100
=(10 + 90) + (20 + 80) + (30 + 70) + (40 + 60) + (50 + 100)
=100 + 100 + 100 + 100 + 150
=100 . 4 + 150
=400 + 150
=550
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Their total ages in three years time is: 31 + (3 . 3)=40(years)
Answer:40 years
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1000+2500+2000+8000+7500+9000 105+120+480+395
=(1000+9000)+(2500+7500)+(2000+8000) =(105+395)+(120+480)
=10000+10000+10000 =500+600
=30000 =1100
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The volume of the figure is:
[(8 . 4) : 2] . 10=160 (cm3)
Answer:160 cm3
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M=\(\dfrac{5}{7}\) . \(\dfrac{5}{11}\) + \(\dfrac{5}{7}\) . \(\dfrac{2}{11}\) - \(\dfrac{5}{7}\) . \(\dfrac{14}{11}\)
=\(\dfrac{5}{7}\) . (\(\dfrac{5}{11}\) + \(\dfrac{2}{11}\) - \(\dfrac{14}{11}\))
=\(\dfrac{5}{7}\) . \(\dfrac{-7}{11}\)
=\(\dfrac{-5}{11}\)
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A=\(\dfrac{1.1.2.2.3.3.4.4}{1.2.2.3.3.4.4.5}\)=\(\dfrac{1}{5}\)
=>A=\(\dfrac{1}{5}\)