75+12+43+25+88+50+57

=(75+25)+(12+88)+(43+57)+50

=100+100+100+50

=100x3+50

=300+50

=350

               We have

The maximum value of each die is 6, so the maximum value of the sum of 2 dice is : 6 + 6 = 12. Hence, the sum can be 8, 10 or 12.

So, dice can be (2 ; 6) ; (4 ; 4) ; (6 ; 2) ; (4 ; 6) ; (6 ; 4) ; (6 ; 6)

Answer is 6/36=1/6

WE have

I found the number that STAR present is STAR=8712

Cause RATS⋅4=STAR=2178⋅4=8712

So the value of S+T+A+R is 8 + 7 + 1 + 2 = 18.

Answer:18

P=4/5(x+y)+(6/5x+30/x)+(y/5+5/y)≥45.10+2√6/5x.30/x+2√y/5.5/y

=8+12+2=22=8+12+2=22

minP=22⇔x=y=5⇔x=y=5

Answer:1−5⋅2+10⋅22−10⋅23+5⋅24−251−5⋅2+10⋅22−10⋅23+5⋅24−25

=1−5⋅2+5⋅23−5⋅24+5⋅24−25=1−5⋅2+5⋅23−5⋅24+5⋅24−25

=1−5⋅2+5⋅23−25=1−5⋅2+5⋅23−25

=1−5⋅(2−23)−25=1−5⋅(2−23)−25

=1−5.(−6)−32=1−5.(−6)−32

=1+30−32=−1

Its semiperimeter is less than or equal to : 150 : 2 = 75 (cm)

The maximum possible width of one of these rectangles is :

(75 - 1) : (3 + 1) = 18,5 (cm)

Answer:18,5 cm

We have:

4^20=(2^2)^20=2^40

=>2^40=4^20

We have:

8^20=(2^3)^20=2^80

=>8^20=2^80

We have:

2^40=(2^2)^20=4^20

=> 2^40=4^20

We have:

2^30=(2^3)^10=8^10<9^10=(3^2)^10=3^20

=> 2^30<3^20

   75+29+25+30+71

=(75+25)+(29+71)+30

=100+100+30

=200+30

=230

there are 24 

Các cặp:

   63+16+37+50+50

=(63+37)+(50+50)+16

=100+100+16

=100x2+16

=200+16

=216

34+23=57

   80+30+15+70+85+20

=(80+20)+(30+70)+(15+85)

=100+100+100

=100x3

=300

   60+17+30+70+83

=(30+70)+(17+83)+60

=100+100+60

=100x2+60

=200+60

=260

  69+21+79+38+31+62

=(69+31)+(21+79)+(38+62)

=100+100+100

=100x3

=300

   72+13+38+28+87

=(72+28)+(13+87)+38

=100+100+38

=100x2+38

=200+38

=238