\(\dfrac{2}{7}-\left(\dfrac{3}{8}+\dfrac{9}{7}\right)=\dfrac{2}{7}-\left(\dfrac{21}{56}+\dfrac{72}{56}\right)=\dfrac{2}{7}+\dfrac{93}{56}=\dfrac{16}{56}+\dfrac{93}{56}=\dfrac{109}{56}\)

Numbers are too big

= 2023824

123+321=444

1234+4321=4444