The title is missing some information: Each person has a pancake.

So there are: \(4.3.9=108\left(people\right)\) in the party.

The probability that Xera has a four is: \(1:6=\dfrac{1}{6}\)

The probability that Yeta has a four is: \(4:52=\dfrac{1}{13}\) (A standard deck has 4 cards of four)

So the probability that Yeta wins is: \(\dfrac{1}{13}:\left(\dfrac{1}{6}+\dfrac{1}{13}\right)=\dfrac{6}{19}\)

Whatever x is, the median will still be 5 or 6 (If x > 5 than the median is 5 and 6, if x < 5 than the median is 5 and if x = 5 than the median will be 5). So there will be 2 possible values for x.

It is impossible to combine only 2 different-value tokens because 5+19, 11+19, 5+11 \(⋮̸\) 56

Add three different tokens we have: \(5+11+19=35\left(points\right)\)

We have: \(56-35=21\) (points) left when we add two tokens.

Because 21 points worth 2 5-point tokens and a 11-point token so in the box, there are:

+ 3 5-point tokens

+ 2 11-point tokens

+ 1 19-point tokens

Because it is divisible by 8 so the numbers will be 8aa8 (because it is a four-digit palindrome number)

We have:

+ 8998 \(⋮̸\) 7 (Unsatisfy)

+ \(8888⋮̸\) 7 (Unsatisfy)

+ 8778 \(⋮\) 7 (Satisfy)

So the greatest four-digit palindrome is 8778

The numbers of years (in the 21st century) must \(\ge\)13 [Because the last month of the year is December (12) ] and \(\le\) 42 [Because the greatest day cound have (31) and the last month of the year is December (12)]. So there are: \(42-13+1=30\left(years\right)\) have a sum date in each month of the year.

We have: 32! = \(2.3.2^2.5.\left(2.3\right).7.2^3.9.\left(2.5\right).11.\left(2^2.3\right).13.\left(2.7\right).15.2^4.17.\left(2.9\right).19.\left(2^2.5\right).21.\left(2.11\right).23\)

\(.\left(2^3.3\right).25.\left(2.13\right).27.\left(2^2.7\right).29.\left(2.15\right).31.2^5\)

So the greatest integral value of n which 32! has \(2^n\) as a factor is: \(1+2+1+3+1+2+1+4+1+2+1+3+1+2+1+5=31\)

(the sum of all index of the number \(2^x\))

ANSWER: 31

Their absolute difference is: \(\left|1,18-2,36\right|=\left|2,36-1,18\right|=1,18\)

KEITA FC 8C // Fc Alan Walker // DJ shape of you // Hủy diệt the world // FA Thần Tốc độ // Fc năng lượng hạt nhân.

These nicks were used by 1 user. The main account (KEITA FC 8C) were used for answering 5 other accounts [A4: Auto Ask Auto Answer]. I suggested Summer Clouds should have a solution for this.

In each hundreds from 222 - 999, there are \(299-222+1=78\left(extensions\right)\)/each hundreds

From 222 - 999 there are: \(9-2+1=8\left(hundreds\right)\)

So there are: \(78\cdot8=624\) unique three-digit extensions can be assigned.

The ratio of the walkway's rate to Becca and Varun's walking speed (same constant speed) is:

\(\left(1-\dfrac{2}{5}\right):\dfrac{2}{5}=\dfrac{3}{5}:\dfrac{2}{5}=\dfrac{3}{2}\)

The bathroom needs to be tilted: \(\left(12^2\right):\left(1^2\right)=144\left(tiles\right)\)

Because the bathroom has 4 edges (the bathroom's shape is square) so the probability is: \(\dfrac{4}{144\cdot\left(144-1\right)}=\dfrac{4}{20592}=\dfrac{1}{5148}\)

The price of a box of pens now costs: 100% - 10%  90%

The percentage of the pens in the box now is: 100% - 25% = 75%

The percent change in the cost per pen is: \(\left(90\%:75\%\right)-100\%=20\%\)

ANSWER: 20%

\(77^7=1,604852327\cdot10^{13}\)

The exact number of weeks of Martian year each year is: \(668:7=95\dfrac{3}{7}\left(weeks\right)\)

So the fraction of the years are leap years is: \(95\dfrac{3}{7}-95=\dfrac{3}{7}\) 

We have: \(n< 1\) and \(n>2\) not satisfy the question.

So n = 1 and n = 2 satisfy the question.

Because 2 > 1 so 2 is the greatest integer n.

Convert: 1 foot = 12 inches.

The volume of the cylindrical pool is: \(4,5\cdot\left(12\cdot12\cdot\pi\right)=4,5\cdot144\pi=648\pi\approx2035,75\left(ft^3\right)=24429\left(in^3\right)\)

So the cost for Maxwell to fill his pool is: \(\left(24429:231\right)\cdot0,15\approx15,86\approx16\left(cents\right)\)

Because the word ALGEBRA has 6 different letters so we have 6 slips of paper for this word.

So the probability is: \(\dfrac{6}{26\left(26-1\right)}=\dfrac{6}{650}=\dfrac{3}{325}\)