let go backward!

also ,u can watch this :https://www.youtube.com/watch?v=Mc6VA7Q1vXQ

we will call the captian A and other B,C,D,E.

if there only 2 pirate left,the captain(D) will take all the coin .E couldnt help because she only have 1 vote.

if there are 3 pirate left,the captain (C) will take 99 coin and give E 1 coin. E will accept the plan (because if she dont,she wont have any coin).So,C and E will accept,and D wont

If there are 4 pirate left,the captain(B) will take 99 coin and give D a coin.D will accept because if he dont,he have nothing.So B and D will accept and E and C wont.

Now back to our problem!

There are 5 pirate left. If B be the captian,E and C wont have any coin.So let give them a coin!We will take 98 coin and then E and C each have a coin.That way A ,E,C will vote for us and B and D wont.

That is the best(?) way to get at much coin at posable

Sorry if my English is wrong .