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Nguyễn Thị Thúy Ngân

so clever

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  • Nguyễn Thị Thúy Ngânanswered a question

    14/08/2017 at 22:08

    \(\dfrac{1}{1.2.3}+\dfrac{1}{2.3.4}+...+\dfrac{1}{a.\left(a+1\right).\left(a+2\right)}=\dfrac{a.\left(a+3\right)}{4.\left(a+1\right)\left(a+2\right)}\)

    Can you for me!yeu

  • Nguyễn Thị Thúy Ngânfollowed a question

    14/08/2017 at 16:00

    Calculate :

    \(\dfrac{1}{1.2.3}+\dfrac{1}{2.3.3}+.....+\dfrac{1}{a+\left(a+1\right)+\left(a+2\right)}\)

    Source : Câu hỏi của Đào Minh Quang - Toán lớp 7 - Học toán với OnlineMath

    Who can find the value =)))) 

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