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Võ Kim Tuấn Anhfollowed a question
10/07/2017 at 09:29
Compare $A=\dfrac{4^2.3^{10}}{2^3.9^5}$ and $B=1$
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10/07/2017 at 09:36
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10/07/2017 at 13:53
$\frac{2}{5} + \frac{4}{6} + \frac{1}{7} + \frac{3}{5} + \frac{1}{3} + \frac{6}{7}$

$= (\frac{2}{5} + \frac{3}{5}) + (\frac{2}{3} + \frac{1}{3}) + (\frac{1}{7} + \frac{6}{7})$

$= 1 + 1 + 1 = 3$
Võ Kim Tuấn Anhanswered a question
07/07/2017 at 19:40
5x (x - 2000) - x + 2000 = 0

5x (x - 2000) - (x - 2000) = 0

(5x - 1) (x - 2000) = 0

⇔[5x-1=0x-2000=0⇒[X=15x=2000
Võ Kim Tuấn Anhanswered a question
04/07/2017 at 18:47
20000
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04/07/2017 at 17:16
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04/07/2017 at 18:46
100000
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04/07/2017 at 18:45
600 mk cho bạn rồi
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04/07/2017 at 17:25
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04/07/2017 at 15:31
99 cây
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04/07/2017 at 12:49
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14/06/2017 at 12:58
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04/07/2017 at 15:19
Thái Sơn
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04/07/2017 at 15:19
lịch sử
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04/07/2017 at 15:18
4 con vịt
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04/07/2017 at 15:17
1000000
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04/07/2017 at 07:38
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04/07/2017 at 07:36
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04/07/2017 at 07:34
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04/07/2017 at 15:15
Số học sinh nam trong trường là: 1000 - 570 = 430

Số học sinh đi du học bằng xe buýt là: 1000: 4 = 250

Số trẻ em trai đi học bằng xe buýt là: 430 - 313 = 117

Số cô gái đến trường bằng xe buýt là: 250 - 117 = 133

Trả lời: 133 cô gái

Võ Kim Tuấn Anh

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