Center of the circle: ABC

=> AB = BC = AC = 2R = 4

=> ABC is a equilateral triangle

The area for the shaded region: S

The area for a sector definition by A and 2 tangential points: S_A

S = S_ABC - 3S_A

S_ABC = \(\dfrac{1}{2}\).4.4.\(\dfrac{\sqrt{3}}{2}\) = 4\(\sqrt{3}\)

S_A = \(\dfrac{60}{360}\)S_circles = \(\dfrac{1}{6}\)\(\pi\)2² = \(\dfrac{2\pi}{3}\)

^{=> S = 4\(\sqrt{3}\)} - 3\(\dfrac{2\pi}{3}\) = 4\(\sqrt{3}\) - 2\(\pi\)

Center of the circle: ABC

=> AB = BC = AC = 2R = 4

=> ABC is a equilateral triangle

The area for the shaded region: S

The area for a sector definition by A and 2 tangential points: SA

S = SABC - 3SA

SABC = 12

.4.4.√32 = 4√3

SA = 60360

Scircles = 16π22 = 2π3

=> S = 4√3

 - 32π3 = 4√3 - 2π

    Center of the circle: ABC

    => AB = BC = AC = 2R = 4

    => ABC is a equilateral triangle

    The area for the shaded region: S

    The area for a sector definition by A and 2 tangential points: SA

    S = SABC - 3SA

    SABC = 12

.4.4.√32 = 4√3

SA = 60360
Scircles = 16π22 = 2π3

=> S = 4√3
 - 32π3 = 4√3 - 2π