Let x is the area to calculate. We see that  EAD is equilateral triangle with the edge equal to 1, the equilateral line equal to \(\dfrac{\sqrt{3}}{2}\) . So \(EF=1-\dfrac{\sqrt{3}}{2}\) .

We have  the angle EDC is \(30^0\) ,  so that \(\dfrac{1}{2}.\dfrac{1}{2}\left(1-\dfrac{\sqrt{3}}{2}\right)-\dfrac{x}{2}=\dfrac{\pi}{12}-\dfrac{1}{2}.1.1.\sin30^0=\dfrac{\pi}{12}-\dfrac{1}{4}\)

So   \(x=1-\dfrac{\sqrt{3}}{4}-\dfrac{\pi}{6}\) .

Let x is the area to calculate. We see that  EAD is equilateral triangle with the edge equal to 1, the equilateral line equal to √32 . So EF=1−√32

 .

We have  the angle EDC is 300

 ,  so that 12.12(1−√32)−x2=π12−12.1.1.sin300=π12−14

So   x=1−√34−π6

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