Hán Quang Dũng
30/08/2018 at 06:33-
Huỳnh Anh Phương 30/08/2018 at 13:47If :
\(\left(20x-10\right).8.\left(15x+2\right)=0\)
=> 20.x - 10 = 0 or 15.x + 2 = 0
* 20 .x -10 = 0 * 15 . x + 2 = 0
20 . x = 0 + 10 15 .x = 0 - 2
20 . x = 10 15 .x = - 2
x = 10 : 20 x = - 2 : 15
x = \(\dfrac{1}{2}\) x = \(\dfrac{-2}{15}\)
So : x = \(\dfrac{1}{2}\) ; x = \(\dfrac{-2}{15}\)
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Hán Quang Dũng 30/08/2018 at 06:40
I am sorry
Question exactly:
Find x \(\left(20x-10\right).8.\left(15x+2\right)=0\)
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# ¤ PUBG ¤ # 18/01/2019 at 09:51If :
(20x−10).8.(15x+2)=0
=> 20.x - 10 = 0 or 15.x + 2 = 0
* 20 .x -10 = 0 * 15 . x + 2 = 0
20 . x = 0 + 10 15 .x = 0 - 2
20 . x = 10 15 .x = - 2
x = 10 : 20 x = - 2 : 15
x = 12
x = −215
So : x = 12
; x = −215