Huy Toàn 8A (TL)
03/08/2018 at 13:08-
Mạnh Khôi 03/08/2018 at 15:47\(\dfrac{x}{3}-\dfrac{2x+1}{2}=\dfrac{x}{6}-x\)
\(\Leftrightarrow\dfrac{2x}{6}-\dfrac{3\left(2x+1\right)}{6}=\dfrac{x}{6}-x\)
\(\Leftrightarrow x=\dfrac{x}{6}-\dfrac{2x}{6}+\dfrac{3\left(2x+1\right)}{6}\)
\(\Leftrightarrow x=\dfrac{x-2x+3\left(2x+1\right)}{6}\)
\(\Leftrightarrow x=\dfrac{-x+6x+3}{6}\)
\(\Leftrightarrow x=\dfrac{5x+3}{6}\)
\(\Leftrightarrow6x=5x+3\)
\(\Leftrightarrow6x-5x=3\)
\(\Leftrightarrow x=3\)
So the value of x is 3
Huy Toàn 8A (TL) selected this answer.