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Huy Toàn 8A (TL)

02/08/2018 at 07:07
Answers
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Find \(x;y;z\)

\(\dfrac{12x-15y}{7}=\dfrac{20z-12x}{9}=\dfrac{25y-12z}{11}\)

and \(x+y+z=48\)


Math 7


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  • ...
    Cristiano Ronaldo 02/08/2018 at 11:54

    Find x;y;zx;y;z

    12x−15y7=20z−12x9=25y−12z1112x−15y7=20z−12x9=25y−12z11

    and x+y+z=48x+y+z=48

    Answer: x=12 ; y=15 , z=21 ( i think so)
  • ...
    Huy Toàn 8A (TL) 02/08/2018 at 13:55

    You should answer question  clearly

  • ...
    Huy Toàn 8A (TL) 02/08/2018 at 13:48

    Question clearly


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