Quoc Tran Anh Le Coordinator
27/07/2018 at 06:28-
Tôn Thất Khắc Trịnh 28/07/2018 at 16:53
Case 1: Following what was given in the question, the original price of the second shirt is \(\dfrac{130\%}{70\%}=185,\left(714285\right)\%\)of the first shirt's original price.
So the total loss is \(\left(185,\left(714285\right)\%+100\%\right)-2\cdot130\%=25,\left(714285\right)\%\)of the first shirt's original price.Case 2: Following what was given in the question, the original price of the first shirt is \(\dfrac{70\%}{130\%}=53,\left(846153\right)\%\)of the second shirt's original price
So the total loss is \(\left(53,\left(846153\right)+100\%\right)-2\cdot70\%=15,\left(846153\right)\%\)of the second shirt's original price.WHAT'S UP WITH THESE QUESTIONS WITH SUCH AMBIGUOUS PERCENTAGES?
Quoc Tran Anh Le selected this answer.
Anyways, the numbers are quite... odd and the solution for them seems really inappropriate for any math question ever so I think I might be wrong, but I don't know how to understand the question in any other way so... UWU