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Quoc Tran Anh Le Coordinator

27/07/2018 at 06:27
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Michael wanted to tie 20 ropes. The length of each rope was 50 cm. 5 cm of one end of a rope was tied to 5 cm of one end of another rope. Each of the resulting knots was 5 cm long. What was the length of the new rope? 


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    Tôn Thất Khắc Trịnh 28/07/2018 at 16:27

    I don't understand this question that well... but I'll try my hardest.

    I would think of it this...undefined
    So there would be \(20-1=19\)(knots) assuming that Michael isn't stupid enough to tie a ROPE into a freaking CIRCLE. And those knots would be \(19\cdot5=95\)(cm) in total
    For the 18 lengths in the middle, each of them will have sacrificed 5cm on each end, therefore sacrificing 10cm in total, leaving only \(50-10=40\)(cm) if we are not counting the knots, so all of them would be \(40\cdot18=720\)(cm)
    The two end lengths are different, because each of them will sacrifice only 5cm, making each of them \(50-5=45\)(cm) and making \(45\cdot2=90\)(cm) when we count all of the end lengths.
    So in the end, we have a \(40+720+90=850\)(cm) rope. Not bad, Michael.

    Quoc Tran Anh Le selected this answer.
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    Tôn Thất Khắc Trịnh 28/07/2018 at 16:31

    https://imgur.com/w5IOA1h
    Ugh, please MathYou staff, try and fix the uploading images problem. For the time, I'm just going to use imgur. And for those of you who don't know what imgur is, don't worry, it's not any viruses, just simple images posted online via a link.



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