MathYouLike MathYouLike
  • Toggle menubar
  • Toggle fullscreen
  • Toggle Search
  •    Sign up
  • QUESTIONS
  • TAGS
  • USERS
  • BADGES
  • UNANSWERD
  • ASK A QUESTION
  • BLOG
...

Uchiha Sasuke

24/07/2018 at 02:12
Answers
2
Follow

A rectangle has length p cm and breadth q cm, where p and q are integers and p and q satisfy the equation pq + q = 13 + q2 then the maximum possible area of the rectangle is...


area


    List of answers
  • ...
    Tôn Thất Khắc Trịnh 24/07/2018 at 13:22

    OwO, it's a typo: it's suppossed to be width, okay?
    If you use the AMGM theorem, you'll know that any rectangle achieves the maximum possible area when both of their measurements are equal, making it a square (a square is technically a rectangle too)
    So we have p=q
    Therefore, the equation will be q2+q=13+q2
    <=>q=13(cm)
    <=>p=q=13(cm)
    <=>S=pq=132=169(cm2)

    (P.S: don't do this here, cuz you'll get to a dead end, oof)
    \(pq+q=13+q^2\)
    \(\Leftrightarrow S=q^2-q+13\)
     

    Selected by MathYouLike
  • ...
    Uchiha Sasuke 24/07/2018 at 13:34

    OMG OMG THANK YOU SO VERY MUCH!!!!!!!!!!!!!!!!!!!!! :DDDDDDDDDDDD


Post your answer

Please help Uchiha Sasuke to solve this problem!



Weekly ranking


© HCEM 10.1.29.225
Crafted with by HCEM