Lê Quốc Trần Anh Coordinator
19/07/2018 at 02:20-
Mạnh Khôi 20/07/2018 at 03:50We have :
\(\left\{{}\begin{matrix}x+2y+3z=6\\2x+3y+z=8\\3x+y+2z=10\end{matrix}\right.\)
\(\Rightarrow x+2y+3z+2x+3y+z+3x+y+2z=6+8+10\)
\(\Rightarrow6x+6y+6z=24\)
\(\Rightarrow6\left(x+y+z\right)=24\)
\(\Rightarrow x+y+z=4\)
So, the value of x + y + z equals : \(4\)
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