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" LEAGUE OF LEGENDS "

27/06/2018 at 09:24
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Let a, b, c be other numbers 0 satisfying : \(\left\{{}\begin{matrix}\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}=\dfrac{1}{a+b+c}\\a^3+b^3+c^3=2^9\end{matrix}\right.\)

Calculate  \(p=a^{2019}+b^{2019}+c^{2019}\)





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