Kayasari Ryuunosuke
22/03/2017 at 21:18-
a) With 2x + 3 = x + 2
=> 2x - x = 2 - 3
=> x = -1
With 2x + 3 = -(x + 2)
=> 2x + 3 = -x - 2
=> 2x + x = -2 - 3
=> 3x = -5
=> x = \(\dfrac{-5}{3}\)
So x = -1 and x = \(\dfrac{-5}{3}\)
b) We have :
A = |x - 2006| + |2007 - x| \(\ge\) |x - 2006 + 2007 - x| = |1| = 1
\(\Leftrightarrow\left\{{}\begin{matrix}\left|x-2006\right|\le0\\\left|2007-x\right|\le0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=2006\\x=2007\end{matrix}\right.\)
So when x = 2006 ; 2007 then value of A smallest
Kayasari Ryuunosuke selected this answer. -
Trịnh Đức Phát 22/03/2017 at 21:27
a) With 2x + 3 = x + 2
=> 2x - x = 2 - 3
=> x = -1
With 2x + 3 = -(x + 2)
=> 2x + 3 = -x - 2
=> 2x + x = -2 - 3
=> 3x = -5
=> x = −53
So x = -1 and x = −53
b) We have :
A = |x - 2006| + |2007 - x| ≥ |x - 2006 + 2007 - x| = |1| = 1
⇔{|x−2006|≤0|2007−x|≤0⇒{x=2006x=2007
So when x = 2006 ; 2007 then value of A smallest
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๖ۣۜGiang๖ۣۜ 23/03/2017 at 17:41
a) With 2x + 3 = x + 2
=> 2x - x = 2 - 3
=> x = -1
With 2x + 3 = -(x + 2)
=> 2x + 3 = -x - 2
=> 2x + x = -2 - 3
=> 3x = -5
=> x = −53
So x = -1 and x = −53
b) We have :
A = |x - 2006| + |2007 - x| ≥ |x - 2006 + 2007 - x| = |1| = 1
⇔{|x−2006|≤0|2007−x|≤0⇒{x=2006x=2007
So when x = 2006 ; 2007 then value of A smallest
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Nễu Lả Ánh 24/03/2017 at 17:34a) With 2x + 3 = x + 2
=> 2x - x = 2 - 3
=> x = -1
With 2x + 3 = -(x + 2)
=> 2x + 3 = -x - 2
=> 2x + x = -2 - 3
=> 3x = -5
=> x =
So x = -1 and x =
b) We have :
A = |x - 2006| + |2007 - x| |x - 2006 + 2007 - x| = |1| = 1
So when x = 2006 ; 2007 then value of A smallest
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Nguyễn Đỗ minh Châu 24/03/2017 at 20:11
Với 2x + 3 = x + 2
=> 2x - x = 2 - 3
=> X = -1
Với 2x + 3 = - (x + 2)
=> 2x + 3 = -x - 2
=> 2x + x = -2 - 3
=> 3x = -5
=> X = - 5 3
X = -1 và x = - 5 3
B) Chúng ta có:
A = | x - 2006 | + | 2007 - x | ≥ | x - 2006 + 2007 - x | = | 1 | = 1
⇔ { | X - 2006 | ≤ 0 | 2007 - x | ≤ 0 ⇒ { x = 2006 x = 2007
Vì vậy, khi x = 2006; 2007 thì giá trị A nhỏ nhất
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Nễu Lả Ánh 24/03/2017 at 17:34a) With 2x + 3 = x + 2
=> 2x - x = 2 - 3
=> x = -1
With 2x + 3 = -(x + 2)
=> 2x + 3 = -x - 2
=> 2x + x = -2 - 3
=> 3x = -5
=> x =
So x = -1 and x =
b) We have :
A = |x - 2006| + |2007 - x| |x - 2006 + 2007 - x| = |1| = 1
So when x = 2006 ; 2007 then value of A smallest
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Nễu Lả Ánh 24/03/2017 at 17:34a) With 2x + 3 = x + 2
=> 2x - x = 2 - 3
=> x = -1
With 2x + 3 = -(x + 2)
=> 2x + 3 = -x - 2
=> 2x + x = -2 - 3
=> 3x = -5
=> x =
So x = -1 and x =
b) We have :
A = |x - 2006| + |2007 - x| |x - 2006 + 2007 - x| = |1| = 1
So when x = 2006 ; 2007 then value of A smallest
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Lê Nho Khoa 23/03/2017 at 21:00
a) With 2x + 3 = x + 2
=> 2x - x = 2 - 3
=> x = -1
With 2x + 3 = -(x + 2)
=> 2x + 3 = -x - 2
=> 2x + x = -2 - 3
=> 3x = -5
=> x = −53
So x = -1 and x = −53
b) We have :
A = |x - 2006| + |2007 - x| ≥ |x - 2006 + 2007 - x| = |1| = 1
⇔{|x−2006|≤0|2007−x|≤0⇒{x=2006x=2007
So when x = 2006 ; 2007 then value of A smallest