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Uchiha Sasuke

18/06/2018 at 03:54
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Let # be defined by a # b = ab + a2 + b2. Let @ be defined by \(a@b=\dfrac{a}{3}-b\). 
Calculate (a # b)@ a for a = 15 and b = 6.




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    Nguyễn Mạnh Hùng 18/06/2018 at 08:23

    For a = 15 and b = 6.

    => a # \(b=15.6+15^2+6^2=90+225+36=375\)

    (a#b)@a = \(\dfrac{375}{3}\)- a = 125 - 15 = 110 

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    Uchiha Sasuke 18/06/2018 at 12:23

    Thank you very much haha


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