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Lê Quốc Trần Anh Coordinator

13/06/2018 at 02:03
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Prove that if \(a\ge3\), \(b\ge3\), \(a^2+b^2\ge25\) then \(a+b\ge7\)




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  • ...
    Alone 15/06/2018 at 09:39

    Nguyễn Mạnh Hùng 6,99999999 >6 nhé

  • ...
    Nguyễn Mạnh Hùng 16/06/2018 at 01:03

    Oh, right Alone

  • ...
    Nguyễn Mạnh Hùng 15/06/2018 at 07:57

    We have:

    \(a\ge3\) and \(b\ge3\)

    So \(a+b\ge6\)

    If a + b = 6 then a = 3; b = 3

    \(\Rightarrow a^2+b^2=3^2+3^2=18< 25\)

    So \(a+b>6\)

    Or \(a+b\ge7\)


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