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Lê Quốc Trần Anh Coordinator

13/06/2018 at 02:01
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Given abcd = 1. Prove that: \(a^2+b^2+c^2+d^2+ab+cd\ge6\)




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    FC Alan Walker 21/06/2018 at 02:05

    Your title is wrong. Here's a example: \(abcd=1.\left(-1\right).1.\left(-1\right)=1\)but          \(a^2+b^2+c^2+d^2+ab+cd=1+1+1+1+\left(-1\right)+\left(-1\right)=2< 6\)


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