We have:

 x – 2xy + y – 3 = 0

<=> 2x – 4xy + 2y – 6 = 0 <=> 2x – 4xy + 2y – 1 =5

<=> 2x(1 – 2y) – (1 – 2y) = 5 <=> (2x – 1)(1 – 2y) =5

Tabulator : You self make 

=> So \(x\in\left\{\left(1;-2\right),\left(3;0\right),\left(-2;1\right)\right\}\)