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Applying Cauchy's inequality , we have
\(\left(a^4+1\right)+\left(b^4+1\right)\ge2a^2+2b^2=2\left(a^2+b^2\right)\ge2.2ab=4ab\)
Equation occur <=> a = b = \(\pm1\)
Lê Quốc Trần Anh selected this answer. -
Fc Alan Walker 18/05/2018 at 13:34Applying Cauchy's inequality , we have
(a4+1)+(b4+1)≥2a2+2b2=2(a2+b2)≥2.2ab=4ab
Equation occur <=> a = b = ±1