Kaya Renger Coordinator
14/05/2018 at 15:15-
Alone 15/05/2018 at 14:00We have:\(\left(ac+bd\right).\left(ad+bc\right)=0\)
\(\Leftrightarrow a^2cd+bad^2+abc^2+b^2cd=0\)
\(\Leftrightarrow\left(a^2+b^2\right).cd+ba\left(c^2+d^2\right)=0\)
\(\Leftrightarrow2017.ab+2017.cd=0\Leftrightarrow ab+cd=0\)
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Trần Đức Huy 15/05/2018 at 08:12Prove that: a2+b22≥(a+b2)2
