Lê Quốc Trần Anh Coordinator
14/05/2018 at 12:57-
We have
\(\dfrac{\overline{ab}}{\overline{bc}}=\dfrac{b}{c}\Leftrightarrow\dfrac{10a+b}{10b+c}=\dfrac{b}{c}=\dfrac{10a+b-b}{10b+c-c}=\dfrac{10a}{10b}=\dfrac{a}{b}\)
=> \(\dfrac{a}{b}=\dfrac{b}{c}\)
Lê Quốc Trần Anh selected this answer.