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Lê Anh Duy

02/05/2018 at 10:00
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16) Given polynomial f(x) that satisfy: f(x+1) = f(x) + 1 (\(x\in R\)) and f(0) = 1

Find f(x)

 

 




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    Alone 03/05/2018 at 15:52

    \(f\left(1\right)=f\left(0\right)+1=1+1=2\)

    \(f\left(2\right)=f\left(1\right)+1=2+1=3\)

    \(f\left(3\right)=f\left(2\right)+1=3+1=4\)

    ...

    So \(f\left(x\right)=x+1\)

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