Lê Anh Duy
15/04/2018 at 11:51-
¤« 16/04/2018 at 14:03
We have:
CD.DA = 24; FD⋅DA2=9⇒FD⋅DA=18
=> FDCD=1824=34⇒FC=14CD
AB⋅BE2=4⇒AB⋅BE=8
⇒BEBC=824=13⇒EC=23BC
⇒SΔEFC=14CD⋅23BC2=16.242=42=2(cm2)
⇒SΔAEF=24−9−4−2=13(cm2)
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We have:
CD.DA = 24; \(\dfrac{FD\cdot DA}{2}=9\Rightarrow FD\cdot DA=18\)
=> \(\dfrac{FD}{CD}=\dfrac{18}{24}=\dfrac{3}{4}\Rightarrow FC=\dfrac{1}{4}CD\)
\(\dfrac{AB\cdot BE}{2}=4\Rightarrow AB\cdot BE=8\)
\(\Rightarrow\dfrac{BE}{BC}=\dfrac{8}{24}=\dfrac{1}{3}\Rightarrow EC=\dfrac{2}{3}BC\)
\(\Rightarrow S_{\Delta EFC}=\dfrac{\dfrac{1}{4}CD\cdot\dfrac{2}{3}BC}{2}=\dfrac{\dfrac{1}{6}.24}{2}=\dfrac{4}{2}=2\left(cm^2\right)\)
\(\Rightarrow S_{\Delta AEF}=24-9-4-2=13\left(cm^2\right)\)
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Lê Anh Duy 15/04/2018 at 15:14
Hey! Correct explanation but you calculate incorrectly. Try again!