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Lê Anh Duy

15/04/2018 at 10:08
Answers
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6) Given that m = 999...99 and n = 888...88 that both have 2018 digits

Find the sum of the digits of m \(\times\)n




    List of answers
  • ...
    ¤« 16/04/2018 at 14:03

    m.n=(999...99).(888...88)

                    2015            2015

             =(888...88).(1000...00−1)

                    2015             2016

            =(888...88000..00)−(888...88)

                         4030                      2015

            =888...887111...112

                   2014         2014

  • ...
    FC Alan Walker 16/04/2018 at 13:06

    \(m.n=\left(999...99\right).\left(888...88\right)\)

                    2015            2015

             \(=\left(888...88\right).\left(1000...00-1\right)\)

                    2015             2016

            \(=\left(888...88000..00\right)-\left(888...88\right)\)

                         4030                      2015

            \(=888...887111...112\)

                   2014         2014

  • ...
    FC Alan Walker 18/04/2018 at 12:30

    The sum of the digits of m.n is: 8.2014+7+1.2014+2=18135.

  • ...
    Lê Anh Duy 16/04/2018 at 15:05

    Find the sum of the digits?


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