Question by Dao Trong Luan - Discuss with MathYouLike

Dao Trong Luan Coordinator

07/04/2018 at 05:10

Prove that:

\(\dfrac{3}{4}\left(AB+AC+BC\right)< AD+BE+CF< AB+AC+BC\)

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¤« 07/04/2018 at 14:38

i think the title is wrong. It is: 34(AB+AC+BC)<AD+BE+CF<AB+AC+BC
Lê Quốc Trần Anh Coordinator 07/04/2018 at 09:39

I think the title is wrong. It is: \(\dfrac{3}{4}\left(AB+AC+BC\right)< AD+BE+CF< AB+AC+BC\)

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